Which algebraic expression is equivalent to this expression?

Mathematics

1 answer:

Leno4ka [110]2 years ago

3 0

The numerical value of this algebraic expression is 123

Step-by-step explanation:

To solve this algebraic expression, we're going to subtract the numbers indicated in parentheses, and finally, we're going to multiply and <em>add </em>the numbers.

Resolution:

$\large \sf =6(22 - 12) + 63$

$\large \sf =6(10) + 63$

$\large \sf =60 + 63$

$\boxed{\boxed{{\large \sf 123}}}$

Therefore, we can conclude that the numeric value of this expression will be 123

You might be interested in

Which one are correct?

Nesterboy [21]

B and d are correct

8 0

2 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$