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Finger [1]
2 years ago
12

Which results only in a horizontal compression of Y =

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
7 0

Answer:

y=1/6x

Step-by-step explanation:

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Can someone show me at least trial one
GenaCL600 [577]
Pick a number: 5
Add 7: 5+7=12
Triple the result: 12*12*12=1728
Add 9= 1728+9=1737
Divide by 3 = 1737/3=579
Subtract original number = 579-5=574

Now pick a different number a do the same process

Hope that helps
8 0
3 years ago
Read 2 more answers
In the chart of accounts, each account number has two digits. The first digit indicates the major account group to which the acc
Eduardwww [97]

Answer:

The correct option is (b)

Step-by-step explanation:

Chart of accounts refers to listing or arranging various accounts for the ease of locating them. Listing is done based on the order of appearance beginning with balance sheet and then income statement.

The order starts with assets, followed by liabilities and stockholders' equity from the balance sheet and revenue and expenses from income statement.

So, the correct order is stated in option (b).

4 0
3 years ago
Read 2 more answers
Scientific notation
tatiyna

Answer:

51,760

Step-by-step explanation:

Move the decimal place 4 tens places to the right (Positively)

51,760

I hope this helped!

7 0
2 years ago
Im just typing this so i can reach the 20 character the limit :)​
masha68 [24]

Answer:

x = 5

Step-by-step explanation:

Add the degrees of m<VUJ and m<JUT and make them equal to 175 since both angles exist with m<VUT.

17x - 3 + 17x + 8 = 175

34x - 3 + 8 = 175

34x + 5 = 175

34x = 170

x = 5

7 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is
Anastaziya [24]

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, \overline x = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}

We get;

t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t =  2.166587

The p-value is obtained using an online source as p(t ≤  -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

3 0
2 years ago
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