0.750,and 0.955 because both have 5s in the hundredths place
The <em><u>correct answer</u></em> is:
bx + 3y > 6 and y > 2x + 4
Explanation:
Looking at the second inequality, the y-intercept is 4 and the slope is 2. This means the graph of the line crosses the y-axis at (0, 4) and the line goes up 2 and over 1. Since it is greater than, this means the graph is shaded above it. Comparing this to the graph, the line for the blue part crosses the y-axis at (0, 4) and goes up 2 and over 1. The graph is also shaded above the line.
For the first inequality, bx+3y > 6, we want to isolate y. To do this, we subtract bx from each side:
bx+3y-bx > 6-bx
3y > 6-bx
Divide both sides by 3:
3y/3 > 6/3 - bx/3
y > 2 - (b/3)x
This means the line for this will have a y-intercept of 2 and decrease 1 while going over 3. The orange section does this. Additionally, since it is greater than, the graph should be shaded above the line. This one is, so this is the correct answer.
Answer:
the answer is C. 20/27 cubic cm.
Step-by-step explanation:
V = LWH
length 5(1/3 cm)
width 2(1/3 cm)
height 2(1/3 cm)
V = (5/3 cm) (2/3 cm) (2/3 cm)
V = 20/27 cubic cm.
Answer:
The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].
Step-by-step explanation:
The formula to compute the future value is:
![FV=PV[1+\frac{r}{100}]^{n}](https://tex.z-dn.net/?f=FV%3DPV%5B1%2B%5Cfrac%7Br%7D%7B100%7D%5D%5E%7Bn%7D)
PV = Present value
r = interest rate
n = number of periods.
It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.
The expression to compute the amount in the investment account after 14 years is,
![FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}](https://tex.z-dn.net/?f=FV%3D5000%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%5E%7B14%7D%2B3000%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%5E%7B14-6%7D%5C%5CFV%3D5000%5B1%2B0.10%5D%5E%7B14%7D%2B3000%5B1%2B0.10%5D%5E%7B8%7D)
The future value is:
![FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27](https://tex.z-dn.net/?f=FV%3D5000%5B1%2B0.10%5D%5E%7B14%7D%2B3000%5B1%2B0.10%5D%5E%7B8%7D%5C%5C%3D18987.50%2B6430.77%5C%5C%3D25418.27)
Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].
