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velikii [3]
3 years ago
12

Cody is selling chocolate and white chocolate candy bars for a school fundraiser. 30% of the candy bars sold have been white cho

colate. If Cody has sold 24 white chocolate candy bars, how many total candy bars has he sold?
Mathematics
1 answer:
bogdanovich [222]3 years ago
3 0
30% of 24 is 7.2, which can be rounded to 7 white chocolate candy bars.
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Solve for b......<br> 15b=5
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The answer is b=3. divide 5 into 15                    

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
Let r and s be the roots of x^2 - 6x + 2 = 0. Find (r - s)^2.
Sphinxa [80]

Answer: (r-s)^{2} = 28

Step-by-step explanation:

  • x^{2} -6x+9=-2+9
  • (x-3)^{2}=7
  • (x-3)= -\sqrt{7} or \sqrt{7} <-- there's no plus/minus sign.
  • (x-3) = -\sqrt{7}
  • x = 3 -\sqrt{7} <-- root.
  • (x-3) = \sqrt{7}
  • x = 3+\sqrt{7} <-- root.
  • [(3-\sqrt{7})-(3+\sqrt{7})]^{2}
  • (3-\sqrt{7} -3 - \sqrt{7})^{2} <-- don't forget to distribute the negative.
  • (-2\sqrt{7})^{2}
  • (4)(7)
  • 28
4 0
2 years ago
Pls help
zzz [600]
Answer: 40%

8+4+8 =20, there’s 8 tomato plants so 20/8=0.4
3 0
2 years ago
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