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3 years ago

12

Cody is selling chocolate and white chocolate candy bars for a school fundraiser. 30% of the candy bars sold have been white cho

colate. If Cody has sold 24 white chocolate candy bars, how many total candy bars has he sold?

1 answer:

bogdanovich [222]3 years ago

3 0

30% of 24 is 7.2, which can be rounded to 7 white chocolate candy bars.

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3.52 in expanded form

Scrat [10]

Step-by-step explanation:

3.52 =

3

+ 0.5

+ 0.02

hopes this helps you

6 0

2 years ago

Write an equation of the line that passes through the given point and is parallel to the given line.

9966 [12]

Answer : <em>Equation of line is</em> y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = $\frac{2}{3}$ x+1 is m= $\frac{2}{3}$

We know that line : y = $\frac{2}{3}$ x+1 is parallel to equation of target line.

therefore, slope of target line will be $\frac{2}{3}$ .

we write equation of target line as y= $\frac{2}{3}$ x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= $\frac{2}{3}$ x+c

-2= $\frac{2}{3}$ $\times$ -5+ c

-5= $\frac{-10}{3}$ +c

c= $\frac{-5}{3}$

thus, Equation of line is y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

7 0

3 years ago

36 is _______% less than 60?

Arte-miy333 [17]

60*(1-x)=36
60-60x=36
-60x=36-60
-60x=-24
x=24/60
x=4/10
x=2/5
x=0.4

36 is 40% less than 60

4 0

3 years ago

Read 2 more answers

What is equation for the line that is perpendicular to y-3=-4(x+2) and passes through the point (-5,7)

jekas [21]

Answer:

y-7=1/4(x+5)

Step-by-step explanation:

y-3=-4(x+2)

y=-4x-8+3

y=-4x-5

-----------

y-y1=m(x-x1)

y-7=m(x-(-5))

y-7=m(x+5)

perpendicular means negative reciprocal of the slope,

so the slope will be 1/4

y-7=1/4(x+5)

4 0

3 years ago

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago