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kondor19780726 [428]
2 years ago
10

Mrs. Sparks is a 9th-grade Algebra 1 teacher. She teaches three

Mathematics
1 answer:
Marta_Voda [28]2 years ago
6 0

Answer:

ninth grade teacher is going   skipping 30  to each class

Step-by-step explanation:

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14/4 or 7/2

Step-by-step explanation:

6 - (-7)

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When you subtract a - its really just adding

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Find the distance between the two points.<br> (-6, -7) and (154, - 43)
Vitek1552 [10]

Answer:

(160, 36)

Step-by-step explanation:

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2 years ago
Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil
andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that p = 0.26

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that n = 5

4 failures, so 1 success, and we have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898

0.3898 = 38.98% probability that there will be 4 failures

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3 years ago
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