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andreev551 [17]

2 years ago

12

Elena collects 112 specimens of beetle and records their lengths for an ecology research project. When she returns to the labora

tory, Elena finds that she incorrectly recorded one of lengths of the beetles as 122 centimeters (about 4 feet). What should she do with the outlier, 122 centimeters, when she analyzes her data?
please help me, this isn't a (a) (b) (c) (d) option I need a full explanation
40 POINTS!!!

1 answer:

pantera1 [17]2 years ago

7 0

Answer:

The correct option is;

C. She should go back and remeasure all of her specimens again to find the error. If she can't do this, she should eliminate the outlier from the analysis, because this is an error in recording

Step-by-step explanation:

In order to minimize error in measurement, some valuable steps includes;

1) Perform a double check on all measurements to ensure that the measurements recorded are accurate

2) Ensure proper training before taking measurements

3) Measurements should only be taken under controlled conditions

4) Separate the entire population into smaller groups for proper recording

5) Have a second observer double check the records

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The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

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Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

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In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property <u>Power</u> <u>Rule</u> of logarithm:

$log(3)^{\frac{t}{30} }=log15$

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$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

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$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

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