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pickupchik [31]
3 years ago
5

Nial is signing a lease for an apartment that rents for $1020/month. How much will he pay to move in if he must pay the first an

d last months' rent and a security deposit equal to 60% of his monthly rent?
2040


$2448


$2652


$2856
Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0
1020 + 1020 = 2040
%60 of 1020 is:612
2040+612=2652
so third one is true
Ira Lisetskai [31]3 years ago
4 0

Answer:

Option (c) is correct.

He pays $ 2652.

Step-by-step explanation:

Given :   Nial is signing a lease for an apartment that rents for $1020/month.

We have to find the amount he pay to move in if he must pay the first and last months' rent and a security deposit equal to 60% of his monthly rent.

Since, given he must pay the first and last months' rent and a security deposit equal to 60% of his monthly rent.

Given monthly rent is $ 1020

That is 60% of his monthly rent = \frac{60}{100}\times 1020=612

Thus, total amount he needs to pay is  first month rent + last month rent + 60% of his monthly rent.

That is 1020 + 1020 + 612 = 2652.

Thus, He pays $ 2652.

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In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
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Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

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Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

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4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

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Answer:

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Step-by-step explanation:

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Answer:

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