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3 years ago

NEED ASAP PLEASE SHOW WORK! Follow the directions and solve this sequence for the first 10 terms:-3,-12,-48,-192

Mathematics

1 answer:

Novay_Z [31]3 years ago

3 0

Answer: B (786,432)

Geometric sequence follows by multiplying by 4.

-3

-12

-48

-192

-768

-3072

-12288

-49152

-196,608

-786,432

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Three consecutive integers have a sum of 45. Find the integers.

katrin2010 [14]

Answer:

14,15,16

Step-by-step explanation:

14+15=29

add up 29 + 16 = 45

7 0

3 years ago

WILL GIVE BRAINLIEST ANSWER!!!!

nikdorinn [45]

Check first one:
2(-2)- 3(1) < 1
-4 -3 < 1
-7 < 1
This is true, let's check others, just to be sure
Check second one:
2(1/2) - 3(0) < 1
1 - 0 < 1
This is false
Check third one :
2(2)- 3(1) < 1
4- 3 < 1
This is false

So answer is (-2,1)

7 0

3 years ago

Read 2 more answers

How is this solved using trig identities (sum/difference)?

GenaCL600 [577]

FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

$cos \beta = -\frac{1}{2} \sqrt{3}$

$tan \beta= \frac{1}{3} \sqrt{3}$

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
$sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )$
$sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )$
$sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})$

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
$cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )$
$cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )$
$cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )$

Find tan (α - β)
$tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha tan \beta }$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}$

Simplify the denominator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5\sqrt{3}}{24})}$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the numerator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$
$tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the fraction
$tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})$
$tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}$

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3 years ago

This table shows values that represent an exponential function.

mr_godi [17]

Answer:

Step-by-step explanation:

When you go from x=1 to x=3 you go up twice on the x-value. The y value also increases by 6 which means all you have to do is find the average.

6/2= 3

3 is the average increase between x=1 and x=3

Hope this helps!

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2 years ago

Cole bought 7 bricks. All together, the bricks weighed 95.26 pounds. To the nearest thousandth of a pound, how much did each bri

Agata [3.3K]

Answer:

13.608

Step-by-step explanation:

hope I can help man. good luck.

8 0

3 years ago