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3 years ago

Answer pls 3278+32+3213+89321+31398

Mathematics

2 answers:

rewona [7]3 years ago

5 0

Answer:

127,242

Step-by-step explanation:

le calculator helps out a lot

goldenfox [79]3 years ago

3 0

Answer:

oop

Step-by-step explanation:

127247

sorry if wrong I kept getting notifications

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Identify the quadratic term in the function.<br><br>f(x)=2x2−3x+5<br>

Vadim26 [7]

Answer:

2x2-3x-5=0

Step-by-step explanation:

(2x2 - 3x) - 5 = 0

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3 years ago

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A bottling company makes decorative bottles and ships them to their customers. Each bottle has a height of 13 inches and a radiu

patriot [66]

Answer:

Step-by-step explanation:

Volume = πr²h

r = 2.5 inches plus 1inch cushon thickness = 3.5 inch radius.

V = 3.142*3.5²*13

V = 500.56in³

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3 years ago

I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?

garri49 [273]

Answer:

Step-by-step explanation:

The multiples of 3 are

3, 6, 9, 12, 15, ...........

The terms form an arithmetic sequence with common difference of 3.

The sum to n terms is

$S_{n}$ = $\frac{n}{2}$ [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 3, thus

$S_{140}$ = $\frac{140}{2}$ [ (2 × 3) + (139 × 3) ]

= 70(6 + 417) ] = 70 × 423 = 29610 → C

5 0

3 years ago

5. What is the solution to the equation -3(h + 5) + 2 = 4(h + 6) - 9

Klio2033 [76]

Answer: d.h=−4

PLZ MARK BRAINLIEST!

Step-by-step explanation:

Let's solve your equation step-by-step.

−3(h+5)+2=4(h+6)−9

Step 1: Simplify both sides of the equation.

−3(h+5)+2=4(h+6)−9

(−3)(h)+(−3)(5)+2=(4)(h)+(4)(6)+−9(Distribute)

−3h+−15+2=4h+24+−9

(−3h)+(−15+2)=(4h)+(24+−9)(Combine Like Terms)

−3h+−13=4h+15

−3h−13=4h+15

Step 2: Subtract 4h from both sides.

−3h−13−4h=4h+15−4h

−7h−13=15

Step 3: Add 13 to both sides.

−7h−13+13=15+13

−7h=28

Step 4: Divide both sides by -7.

−7h

−7

h=−4

5 0

3 years ago

Read 2 more answers

Help I’m not sure with this one!! Urgent help

Nastasia [14]

This system has exactly one solution, because the two equation are linearly independent (i.e. one is not a multiple of the other).

We can explicitly find the solutions: from the first equation we deduce

$x = \dfrac{c-by}{a}$

Plug this value for x in the second equation:

$\dfrac{a}{3}\cdot \dfrac{c-by}{a}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{c-by}{3}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{2(c-by)+3by}{6}=\dfrac{c}{6}$

Multiply both sides by 6 to get

$2(c-by)+3by=c \iff 2c-2by+3by=c \iff by=-c \iff y=-\dfrac{c}{b}$

Plug this value for y in the expression for x:

$x = \dfrac{c-by}{a} = \dfrac{c-b\cdot\frac{-c}{b}}{a}=\dfrac{2c}{a}$

Since both a,b are not zero, both solutions are well defined.

8 0

3 years ago