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nadezda [96]
3 years ago
5

I will give Brainliest Answer to help me, please

Mathematics
1 answer:
igomit [66]3 years ago
4 0

Answer:

Step-by-step explanation:

What you have are sets A and B and then the Union of those 2 sets.  The Union of sets is like the "marriage" of them.  The 2 sets come together and bring along with them ALL of their junk and they have to share it.

The upside down U indicates the intersection of the sets.  In other words, what they both have in common.  They both share a 5 and a 7.  Therefore, A∩B = {5, 7}

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Which is a diagonal through the interior of the cube?
Wittaler [7]

Answer:

FG i think

Step-by-step explanation:

3 0
2 years ago
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Whats the greatest ten you can multiply by 5 to get close to, but not go over, 335?
Amiraneli [1.4K]
65 is the answer because 65 x 5 =325 which is close but it’s 10 away.
I hope that helped
8 0
3 years ago
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Joel earns $1,700 per month. If he spends $425 on rent each month, what percent of his income does he spend on rent?
a_sh-v [17]
The answer is 25%
you take (425/1700)*100
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4 0
2 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
Pls answer the question fasttt
timurjin [86]
5 : 25  →  (÷5)  → 1 : 5

Answer : 1 : 5
3 0
3 years ago
Read 2 more answers
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