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3 years ago

15

1. What is the range of the function y = 2x-3 when the domain is {-1, 0,5}?

1 answer:

frosja888 [35]3 years ago

4 0

y=2x-3

2x-3

2(-1)-3=-5

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50 POINTS, GEOMETRY + BRAINLIST

erastovalidia [21]

Bisects means to separate in equal parts, meaning each part is equal. This means the equations on each side of the line are equal. Once you equate them, you combine like terms finding your answer.

1) 2x+ 3=x+7
-x -x
x+3 = 7
-3 -3
Answer: x=4 (do this for the others)
2) x=7/2
3) x=5/2

3 0

3 years ago

Please help me figure this out! Thank you so much :( i really need it! ❤️

Hoochie [10]

Answer:

$\textbf{A. }x=2i\text{ or }x=-2i\\\\\textbf{B. }(x+2i)(x-2i)$

Step-by-step explanation:

The quadratic can be solved in a straightforward way:

$x^2+4=0\\\\x^2=-4\qquad\text{subtract 4}\\\\x=\pm\sqrt{-4}\qquad\text{take the square root}\\\\x=\pm2i\qquad\text{simplify}$

This tells you that the solutions are ...

2i or -2i

__

For each root of "a", (x -a) is a factor. Thus the factors of the equation are ...

(x +2i)(x -2i)

8 0

3 years ago

Estimation is useful in all mathematics operations. Tell whether the answer to this problem is sensible 18 - 5 = 23

noname [10]

Answer:

It is not sensible.

explanation:

You are subtracting, so there is no way you could get a larger number. If this was addition, it would be sensible.

4 0

4 years ago

Estimate 7/8 ÷ 11/12 the nearest whole number

swat32

Answer:

21/22

Step-by-step explanation:

(7/8)/(11/12)

(7/8)(12/11)

7*12=84

8*11=88

-----------

84/88

simplify

21/22

Please mark me as Brainliest if you're satisfied with the answer.

8 0

3 years ago

Read 2 more answers

Complete the statements.

spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

$3tan^2(x)-1 =0$

Lets assume tan(x) = u

$3u^2(x)-1 =0$

Now we solve for 'u'

add 1 on both sides

$3u^2(x) =1$ , divide both sides by 3

$u^2 = \frac{1}{3}$

Take square root on both sides

$u = +-\frac{1}{\sqrt{3} }$

We replace tan(x) for 'u'

$tan(x) = +-\frac{1}{\sqrt{3} }$

x = 30 because $tan(30) =+\frac{1}{\sqrt{3} }$ in first quadrant

x = 30 (tan is positive in first quadrant)

$tan(x) =-\frac{1}{\sqrt{3} }$

x = 150 because $tan(150) =-\frac{1}{\sqrt{3} }$ in second quadrant

tan is negative in second quadrant

4 0

4 years ago