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sukhopar [10]
3 years ago
10

Jennifer belongs to a gym that requires a monthly membership fee of $100 plus an additional $10 fee for each yoga class she atte

nds. Which of the following slope-intercept form equations models the total amount that Jennifer pays monthly?
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0
First of all, we need to know what is the slope-intercept form which is:
y=mx+b where m represent slope and b represent y intercept
Then,
Let y represent the total amount of money that Jennifer pays monthly
mx represent the total amount of money that Jennifer pays for classes she attends
b represent the memberships fee, so:
y=10x+100 the following slope-intercept form equations models the total amount that Jennifer pays monthly. Hope it help!
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grandymaker [24]

Answer:

55 degrees (a)

Step-by-step explanation:

complementary means they equal 90 degrees

so 90-35= 55 degrees

3 0
3 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
A high school coach needs to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
AfilCa [17]
If the budget is $200 and he have 15 members then we have divide the two. 200 / 15 = $13.33 per shorts. 15x =< $200. x represents 13.33. So the solution represents the coach may spend up to $13.33 per pair of shorts. If it was even 1 cent more than $13.33 than he wouldn't have enough.So he can spend up to $13.33 or less per pair of shorts.
5 0
3 years ago
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15 points <br> Which graph represents the function g(x) = |x+4|+2?
rewona [7]

Answer:

number 3

Step-by-step explanation:

7 0
3 years ago
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Can Somebody Solve This Equation ?
fiasKO [112]

C= 10+30x

X=9 here so

C= 20+30(9)

So

C=290

4 0
3 years ago
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