Answer:
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
Step-by-step explanation: See Annex
Green Theorem establishes:
∫C ( Mdx + Ndy ) = ∫∫R ( δN/dx - δM/dy ) dA
Then
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy
Here
M = 2x + cosy² δM/dy = 1
N = y + e√x δN/dx = 2
δN/dx - δM/dy = 2 - 1 = 1
∫∫(R) dxdy ∫∫ dxdy
Now integration limits ( see Annex)
dy is from x = y² then y = √x to y = x² and for dx
dx is from 0 to 1 then
∫ dy = y | √x ; x² ∫dy = x² - √x
And
∫₀¹ ( x² - √x ) dx = x³/3 - 2/3 √x |₀¹ = 1/3 - 0
∫ C ( y + e√x) dx + ( 2x + cosy² ) dy = 1/3
HCF=Highest Common Factor-HCF of two or more numbers is the greatest factor that divides the numbers. For example, 2 is the HCF of 4 and 6.
LCM=Least Common Multiple-LCM is the smallest positive number that is a multiple of two or more numbers.
Answers:
1) 6
2) 12
3) 5
4) 3
5) 26
6) 15
7) 88
Answer: the number of students that were surveyed is 40
Step-by-step explanation:
Let x = total number of students that were surveyed about their favorite colors
1/4 of the students preferred red.
This means that the number of students that preferred red is 1/4 × x = x/4
1/8 of the students preferred blue.
This means that the number of students that preferred blue is 1/8 × x = x/8
The remaining number of students will be the total number of students - the sum of the number of students that preferred red and the number of students that preferred blue. It becomes
x - (x/4 + x/8) = x - 3x/8 = 5x/8
3/5 of the remaining students were for green. This means that the number of students that preferred green is 3/5 × 5x/8 = 3x/8
if 15 students prefer green, then
3x/8 = 15
3x = 120
x = 120/3 = 40 students
The triangles are not similar because the smallest sides are 6/10 = 3/5, the medium sides are 8/24 = 1/3, and the longest sides are 10/26 = 5/13 and similar triangles must have the same ratio for all three sides.
Answer:
Step-by-step explanation:
y = 3*x + 4
y = 3*x - 7
Each one of the above equations is the equation for a straight line.
The solution for such a system is the point P ( x₀ , y₀ ) which coordinates belong to both straight lines. According to this, there is only one solution for that system ( only one point of intersection). The intersection of a pair of straight lines either can occur or not depending on the slope of the lines, if they have the same slope they are parallel, then they did not touch each other ever. How can m, be identified in the straight line equation??, just by looking at the coefficient of x.
The two equations have slope 3 they are parallel then there is not a solution ( there is not a common point to both equations)
