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ss7ja [257]
2 years ago
10

Help please match them if you just put a link or say “I don’t know but thanks for the points” I’ll report your answer and you wo

n’t get the brainliest

Computers and Technology
1 answer:
Amanda [17]2 years ago
8 0

Answer:

Input: The user clicks a button

Output: A song is played

User interface: A screen with buttons, images, and text

Explanation:

You might be interested in
Write a telephone lookup program. Read a data set of 1,000 names and telephone numbers from a file that contains the numbers in
morpeh [17]

Answer:

See explaination

Explanation:

PhoneLookup.java

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class PhoneLookup

{

public static void main(String[] args) throws IOException

{

Scanner in = new Scanner(System.in);

System.out.println("Enter the name of the phonebook file: ");

String fileName = in.nextLine();

LookupTable table = new LookupTable();

FileReader reader = new FileReader(fileName);

table.read(new Scanner(reader));

boolean more = true;

while (more)

{

System.out.println("Lookup N)ame, P)hone number, Q)uit?");

String cmd = in.nextLine();

if (cmd.equalsIgnoreCase("Q"))

more = false;

else if (cmd.equalsIgnoreCase("N"))

{

System.out.println("Enter name:");

String n = in.nextLine();

System.out.println("Phone number: " + table.lookup(n));

}

else if (cmd.equalsIgnoreCase("P"))

{

System.out.println("Enter phone number:");

String n = in.nextLine();

System.out.println("Name: " + table.reverseLookup(n));

}

}

}

}

LookupTable.java

import java.util.ArrayList;

import java.util.Collections;

import java.util.Scanner;

/**

A table for lookups and reverse lookups

*/

public class LookupTable

{

private ArrayList<Item> people;

/**

Constructs a LookupTable object.

*/

public LookupTable()

{

people = new ArrayList<Item>();

}

/**

Reads key/value pairs.

atparam in the scanner for reading the input

*/

public void read(Scanner in)

{

while(in.hasNext()){

String name = in.nextLine();

String number = in.nextLine();

people.add(new Item(name, number));

}

}

/**

Looks up an item in the table.

atparam k the key to find

atreturn the value with the given key, or null if no

such item was found.

*/

public String lookup(String k)

{

String output = null;

for(Item item: people){

if(k.equals(item.getName())){

output = item.getNumber();

}

}

return output;

}

/**

Looks up an item in the table.

atparam v the value to find

atreturn the key with the given value, or null if no

such item was found.

*/

public String reverseLookup(String v)

{

String output = null;

for(Item item: people){

if(v.equals(item.getNumber())){

output = item.getName();

}

}

return output;

}

}

Item.java

public class Item {

private String name, number;

public Item(String aName, String aNumber){

name = aName;

number = aNumber;

}

public String getName(){

return name;

}

public String getNumber(){

return number;

}

}

input.txt

Abbott, Amy

408-924-1669

Abeyta, Ric

408-924-2185

Abrams, Arthur

408-924-6120

Abriam-Yago, Kathy

408-924-3159

Accardo, Dan

408-924-2236

Acevedo, Elvira

408-924-5200

Acevedo, Gloria

408-924-6556

Achtenhagen, Stephen

408-924-3522

Note: Replace all the "at" with at symbol

4 0
3 years ago
24/3*2^2/2*3+(20-10)-40
ycow [4]

Answer:

34

Explanation:

You use pemdas

8 0
2 years ago
What is the value of count after this nested FOR loop executes fully.
Alisiya [41]

Answer:

168 (although the =< must be corrected to <=)

Explanation:

int count = 0;

for (int row = 4; row <= 15; row++)

for (int col = 0; col < 13; col = col +2)

count+=2;

The inner for loop runs 7 times (for col = 0,2,4,6,8,10,12). Anything higher is not less than 13. Therefore the inner loop increments count by 2 seven times, i.e. it increments count by 14.

The outer for loop runs 12 times (for row = 4,5,6,7,8,9,10,11,12,13,14,15).

If the count is incremented by 14 twelve times, you are incrementing it by 14*12 = 168.

Therefore the count goes from 0 to 168 after the nested loops.

5 0
3 years ago
Ben chang noticed that his store was lagging in sales . He realized that his staff was not experienced enough . As the store man
dem82 [27]
Ben should set up a program to teach his staff about customer service, and communicating with clients. 
4 0
3 years ago
Read 2 more answers
Suppose that a computer can run an algorithm on a problem of size 1,024 in time t. We do not know the complexity of the algorith
Setler79 [48]

Answer:

Time Complexity of Problem - O(n)

Explanation:

When n= 1024 time taken is t. on a particular computer.

When computer is 8 times faster in same time t , n can be equal to 8192. It means on increasing processing speed input grows linearly.

When computer is 8 times slow then with same time t , n will be 128 which is (1/8)th time 1024.

It means with increase in processing speed by x factor time taken will decrease by (1/x) factor. Or input size can be increased by x times. This signifies that time taken by program grows linearly with input size n. Therefore time complexity of problem will be O(n).

If we double the speed of original machine then we can solve problems of size 2n in time t.

5 0
3 years ago
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