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Elena-2011 [213]

2 years ago

5

Stella is ordering a taxi from an online taxi service. The taxi charges $3 just for the pickup and then an additional $1.75 per

mile driven.

2 answers:

vovikov84 [41]2 years ago

7 0

Answer:

and wht is the question?

Tema [17]2 years ago

3 0

Kk but how far did she go Bc that would be the way to get to the question

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What is negative eight plus four

goldenfox [79]

Answer:

-4

Step-by-step explanation:

- - - - - - - -

+ + + +

4 negatives cancel out and leave you with -4

6 0

2 years ago

Read 2 more answers

The scale of a map is 2 cm : 21 km. find the actual distance for 9 cm on the map.

DIA [1.3K]

I hope this helps you

if 2 cm 21 km

9cm ? km

?×2=9×21

?=189÷2

?=94,5 km

8 0

2 years ago

Read 2 more answers

Help me people please n thank you

arsen [322]

Answer:

the second one g(x){f(x)=x^(2)-2x-2

Step-by-step explanation:

hope this is right

4 0

2 years ago

What is the largest digit N for which 2345N is divisible by 6?

kotegsom [21]

Consider this option (this is not the only way):
1. according to the condition 2345N is divisible by <em>6</em>, it means, that N is even number (0;2;4;6 or 8).
2. <em>6</em>=3*2, then the number 2345N is divisible by 3 also. It means, that the number (2+3+4+5+N)=(14+N) is divisible by 3, where N={0|2|4|6|8}.
3. using items 1 and 2:
(14+4)=18; only 18 is divided by 3, it means that N=4.

answer: 4.

Note also, that only 23451; 23454 and 23457 are divided by 3. Only 2345<u>4</u> is divided by 6 (2345<u>4</u>/6=3909).

3 0

2 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

7 0

3 years ago