Answer:
52 minutes
Step-by-step explanation:
Given in question as
Men 1 = 5 Men 2 = 20
Work 1 = 5 Work 2 = 20
Time 1 = 52 min Time 2 = T 2
Now , we can solve by equating them
i.e
= 
Or,
= 
Or T2 = 52 min Answer
(-1, 5)
(0,0)
(1, -3)
(2, -4)
(3, -3)
(4, 0)
(5, 5)
The answer is 1,7,21,35,35,21,7,1
Answer:
135 and 135
Step-by-step explanation:
The computation is shown below:
The number of examiners who passed in only one subject is as follows
= n(E) - n(E ∩M) + n(M) - n(E ∩M)
= (80 - 60 + 70 - 60)%
= 30%
Now the number of students who passed in minimum one subject is
n(E∪M) = n(E) + n(M) - n(E ∩M)
= 80 - + 70 - 60
= 90%
Now the number of students who failed in both subjects is
= 100 - 90%
= 10% of total students
= 45
So total number of students appeared for this 450
So, those who passed only one subject is
= 450 × 30%
= 135
Now the Number of students who failed in mathematics is
= 100% - Passed in Mathematics
= 100% - 70%
= 30% of 450
= 135