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Llana [10]
3 years ago
9

What is the sum of (5c+9)+(8b-2)+(2m+7)

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

8b + 5c +2m+ 14

Step-by-step explanation:

Firlakuza [10]3 years ago
5 0

Answer:

5c + 8b + 2m + 14

General Formulas and Concepts:

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define expression</u>

(5c + 9) + (8b - 2) + (2m + 7)

<u>Step 2: Simplify</u>

  1. Combine like terms (Z):                    5c + 8b + 2m + 14
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Help its geometry...............
Digiron [165]

m GH = 57''

________


tan 39° = opposite / adjacent

tan 39° = m GH / m HJ

tan 39° *  m HJ = m GH

m HJ = m GH / tan 39°

m HJ ≈ 57'' / 0.810

m HJ ≈ 70.4''    <——<span>—    measure of the segment HJ</span>

________


sin 39° = opposite / hypotenuse

sin 39° = m GH / m GJ

sin 39° * m GJ = m GH

m GJ = m GH / sin 39°

m GJ = 57'' / 0.629

m GJ ≈ 90.6''    <———    measure of the segment GJ

________


So the perimeter is

p  =  m GH  +  m HJ  +  m GJ

p  =  57''  +  70.4''  +  90.6''

p  =  218''    <——<span>—    this is the answer.</span>


I hope this helps. =)


Tags:  <em>perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry</em>

7 0
3 years ago
What’s the students GPA?
andreyandreev [35.5K]

Answer:

The student's GPA is 2.8666.

Step-by-step explanation:

A grade is 4.0, B grade is 3.0, C grade is 2.0. For each credit, add the value of the letter grade. So:

Math, 2 credits, grade A: (4x2=8)

English, 5 credits, grade B: (5x3=15)

Physics, 4 credits, grade B: (4x3=12)

German, 4 credits, grade C: (4x2=8)

The numbers add up to 43, then divide by the number of credits (15) to get:

43/15=GPA of 2.8666.

6 0
3 years ago
You just priced what it would cost to buy vinyl floor tiles at the local tile store. They quoted you $3.29 per tile. When you we
Ad libitum [116K]
(3.29-2.89)/2.89 = .40/2.89 = .1384 or 13.84%
8 0
2 years ago
An equation is shown below:
andreev551 [17]

Answer:

this equation has 1 answer

Step-by-step explanation:

x = 2

3 0
2 years ago
a high school athletic department bought 40 soccer uniforms at a cost of 3000. after soccer season, they returned some of the un
Nana76 [90]
So,

To find the difference between the initial price and the return price, we first need to find the initial price per uniform.  To do that, we will divide the total initial cost of the uniforms by the number of uniforms bought.

\frac{3000}{40} = \frac{300}{4}= \frac{150}{2} =75

Initially, each uniform cost $75.

When they returned some uniforms, they only received $40 per uniform.  What's the difference between that price and the initial price?

75 - 40 = $35

The different between what they paid for each uniform and what they got for each return was $35.
5 0
3 years ago
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