m GH = 57''
________
tan 39° = opposite / adjacent
tan 39° = m GH / m HJ
tan 39° * m HJ = m GH
m HJ = m GH / tan 39°
m HJ ≈ 57'' / 0.810
m HJ ≈ 70.4'' <——<span>— measure of the segment HJ</span>
________
sin 39° = opposite / hypotenuse
sin 39° = m GH / m GJ
sin 39° * m GJ = m GH
m GJ = m GH / sin 39°
m GJ = 57'' / 0.629
m GJ ≈ 90.6'' <——— measure of the segment GJ
________
So the perimeter is
p = m GH + m HJ + m GJ
p = 57'' + 70.4'' + 90.6''
p = 218'' <——<span>— this is the answer.</span>
I hope this helps. =)
Tags: <em>perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry</em>
Answer:
The student's GPA is 2.8666.
Step-by-step explanation:
A grade is 4.0, B grade is 3.0, C grade is 2.0. For each credit, add the value of the letter grade. So:
Math, 2 credits, grade A: (4x2=8)
English, 5 credits, grade B: (5x3=15)
Physics, 4 credits, grade B: (4x3=12)
German, 4 credits, grade C: (4x2=8)
The numbers add up to 43, then divide by the number of credits (15) to get:
43/15=GPA of 2.8666.
Answer:
this equation has 1 answer
Step-by-step explanation:
x = 2
So,
To find the difference between the initial price and the return price, we first need to find the initial price per uniform. To do that, we will divide the total initial cost of the uniforms by the number of uniforms bought.

Initially, each uniform cost $75.
When they returned some uniforms, they only received $40 per uniform. What's the difference between that price and the initial price?
75 - 40 = $35
The different between what they paid for each uniform and what they got for each return was $35.