The answer to the first is 4/15x and the second is x+5
Answer 14.03
Tan 41/1= 12.2/x
Answer:
Option J 13
Step-by-step explanation:
we know that
If applying the Pythagoras Theorem
----> is an obtuse triangle
----> is an acute triangle
----> is a right triangle
where
c is the greater side
<em><u>Verify each case</u></em>
case F) we have
![c=10, a=6, b=8](https://tex.z-dn.net/?f=c%3D10%2C%20a%3D6%2C%20b%3D8)
substitute
![10^{2}> 6^{2} +8^{2}](https://tex.z-dn.net/?f=10%5E%7B2%7D%3E%206%5E%7B2%7D%20%2B8%5E%7B2%7D)
-----> is not true
Is a right triangle
case G) we have
![c=10, a=9, b=8](https://tex.z-dn.net/?f=c%3D10%2C%20a%3D9%2C%20b%3D8)
substitute
![10^{2}> 9^{2} +8^{2}](https://tex.z-dn.net/?f=10%5E%7B2%7D%3E%209%5E%7B2%7D%20%2B8%5E%7B2%7D)
-----> is not true
Is an acute triangle
case H) we have
![c=12, a=8, b=10](https://tex.z-dn.net/?f=c%3D12%2C%20a%3D8%2C%20b%3D10)
substitute
![12^{2}> 8^{2} +10^{2}](https://tex.z-dn.net/?f=12%5E%7B2%7D%3E%208%5E%7B2%7D%20%2B10%5E%7B2%7D)
-----> is not true
Is an acute triangle
case J) we have
![c=13, a=8, b=10](https://tex.z-dn.net/?f=c%3D13%2C%20a%3D8%2C%20b%3D10)
substitute
![13^{2}> 8^{2} +10^{2}](https://tex.z-dn.net/?f=13%5E%7B2%7D%3E%208%5E%7B2%7D%20%2B10%5E%7B2%7D)
-----> is true
Is an obtuse triangle
Answer:
C)
B)
C)
Step-by-step explanation:
<h3>Question-1:</h3>
recall the surface area formula of cylinder
![\displaystyle A _{S} = 2\pi r(h + r)](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D%202%5Cpi%20r%28h%20%2B%20r%29)
given that,h=5 and r=0.7
substitute:
![\displaystyle A _{S} = 2\pi (0.7)(5 + 0.7)](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D%202%5Cpi%20%280.7%29%285%20%2B%200.7%29)
simplify parentheses:
![\displaystyle A _{S} = 2\pi (0.7)(5 .7)](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D%202%5Cpi%20%280.7%29%285%20.7%29)
simplify multiplication:
![\displaystyle A _{S} =25.0572 sqm](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D25.0572%20sqm)
hence, our answer is C
<h3>Question-2:</h3>
remember the surface area formula of cone
![\displaystyle A _{S} = \pi r(r + s)](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D%20%5Cpi%20r%28r%20%2B%20s%29)
given that,r=7 and s=10
substitute:
![\displaystyle A _{S} = \pi (7)(7+ 10)](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D%20%5Cpi%20%287%29%287%2B%2010%29)
simplify parentheses:
![\displaystyle A _{S} = \pi (7)(17)](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D%20%5Cpi%20%287%29%2817%29)
simplify multiplication:
![\displaystyle A _{S} =373.66sqcm](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D373.66sqcm)
hence, our answer is B
<h3>Question-3:</h3>
now for the question-3 we need a little bit understanding
remember the surface area formula of cube
![\displaystyle A _{S} =6 {a}^{2}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7BS%7D%20%3D6%20%7Ba%7D%5E%7B2%7D%20)
we are given that,
Thus
substitute:
![\displaystyle 6 {a}^{2} = 600](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%206%20%7Ba%7D%5E%7B2%7D%20%20%3D%20600)
divide both sides by 6:
![\displaystyle {a}^{2} = 100](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%20%7Ba%7D%5E%7B2%7D%20%20%3D%20100)
square root both sides:
![\displaystyle {a}^{} = 10](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%20%7Ba%7D%5E%7B%7D%20%20%3D%2010)
hence, the measurement of each
edge is 10 cm therefore our answer is C)