Answer: You need approximately 70 g of potassium carbonate.
Explanation:
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Answer:
The transition which is associated with the greatest energy change is from n=1 to n=3.
Explanation:
where,
= energy of orbit
n = number of orbit
Z = atomic number
Energy of n = 1 in an hydrogen like atom:
Energy of n = 2 in an hydrogen like atom:
Energy of n = 3 in an hydrogen like atom:
Energy of n = 5 in an hydrogen like atom:
1) Energy change transition from n = 1 to n = 3 occurs .
Let energy change be E.
(absorption)
2) Energy change transition from n = 2 to n = 1 occurs .
Let energy change be E.
(emission)
3) Energy change transition from n = 3 to n = 2 occurs .
Let energy change be E.
(emission)
4) Energy change transition from n = 3 to n = 5 occurs .
Let energy change be E.
(absorption)
Highest magnitude of energy corresponds to the greatest energy change.So,the transition which is associated with the greatest energy change is from n=1 to n=3.
According to Bronsted-Lowry theory of acids and bases, an acid is proton donor and a base is proton acceptor. When an acid loses the proton, it forms the conjugate base of the acid. Similarly when a base accepts a proton, it forms the conjugate acid if that base. A conjugate acid base pair differs by a single proton.
Given the weak acid . It can lose a proton to form the conjugate base.
Therefore, the conjugate base of is .
Answer:
424 °C
Explanation:
If all other variables are held constant, the missing temperature can be found using the Charles' Law equation:
V₁ / T₁ = V₂ / T₂
In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can plug the given values into the equation and simplify to find the final temperature.
V₁ = 435 mL V₂ = 842 mL
T₁ = 219 °C T₂ = ? °C
V₁ / T₁ = V₂ / T₂ <----- Charles' Law
435 mL / 219 °C = 842 mL / T₂ <----- Insert values
1.9863 = 842 mL / T₂ <----- Simplify left side
(1.9863) x T₂ = 842 mL <----- Multiply both sides by T₂
T₂ = 424 °C <----- Divide both sides by 1.9863
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