The reaction between NaOH and H₂SO₄ is as follows;
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of base to acid is 2:1
NaOH is a strong acid and H₂SO₄ is a strong acid, therefore complete ionization into their respective ions takes place.
number of acid moles reacted - 0.112 M / 1000 mL/L x 39.1 mL = 0.0044 mol
the number of base moles required for neutralisation = 0.0044 x 2 = 0.0088 mol
Number of NaOH moles in 25.0 mL - 0.0088 mol
Therefore in 1000 mL - 0.0088 mol/ 25.0 mL x 1000 mL/L = 0.352 mol/L
Therefore molarity of NaOH - 0.352 M
THe Answer is 105 J
hope this helps and please brainliest, I was first :)
16 protons
Explanation: S2-: proton number 16; nucleon number 32
There are 16 protons (from the proton number). If it was a neutral atom, there would be 16 electrons.
Answer:
Explanation:
If an antacid has sodium hydrogen carbonate/Calcium carbonate, it reacts with HCl as shown
NaHCO₃+ HCl → NaCl + CO₂+ H₂O
Antacid acid salt gas water
CaCO₃+ 2HCl → CaCl₂+ CO₂+ H₂O
Antacid acid salt gas water
The formation of gas CO₂ is shown by brisk effervescence when the antacid (sodium hydrogen carbonate/calcium carbonate) reacts with HCl (acid). So CO₂ is the additional product formed and its formation is supported by observation of brisk effervescence as HCl is added to the antacid.
Answer:
dissolving sugar in water
burning a candle
Explanation: these both have chemical and physical changes happening to them.
