All categories

2 years ago

How do you find the area's square root?

Mathematics

1 answer:

SashulF [63]2 years ago

5 0

The steps to determine the square root of 6241 are:

The digits of 6241 are paired as 62 41.

The unit digit of 6241 is 1. Hence, the possible unit digits after taking square root could be 1 and 9.

When we consider the first two digits of 6241, that are 62.

The number 62 lies between 7 and 8 that is, 49 < 15 < 64 which can be written as 72 < 15 < 82. Hence, the tens digit of the square root of 6241 is 7.

As the number obtained in step 2 is, 1 and 9. The numbers can be 71 or 79.

In order to determine the square root of 6241, we multiply the tens and one's digits in both cases.

62 lies between 72 and 82. Their product gives the value 56.

As 56 < 62, the square root of 6241 will be greater than 71 and 79 which is 79.

Thus, the square root of 6241 is 79.

You might be interested in

HELPPPPPPP ASAPPPPPPPP PLSSSS

Novay_Z [31]

Answer:

the first one is. hope helps

5 0

3 years ago

Ramon has started a workout program. On Monday, he did 10 push-ups. On Tuesday, he did 13 push-

nevsk [136]

Answer:

he will do 19 pushups

Step-by-step explanation:

He will do 19 push ups because the pattern Is going up by 3 each days so if you add 3 to 16 you will get 19!!!!!

Hope This Helped :)

7 0

3 years ago

Read 2 more answers

What is 50x50x50x50? I really need help.

tensa zangetsu [6.8K]

Answer:

6,250,000

4 0

3 years ago

There were 214 people at a concert. Main floor tickets cost $17 and balcony tickets cost $11 for a total of $2954. How may balco

earnstyle [38]

There is 100 $17 tickets no 114 $11 tickets

6 0

3 years ago

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is:

$y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4$

$y = -5.333$

$(x,y) = (2, -5)$ does not belong to the function, the real point is $(x,y) = (2, -5.333)$ .

5 0

3 years ago