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3 years ago

Given: rectangle ABCD is similar to rectangle ZBXY. If BC = 10, BX = 6, XY = 4, then CD =

Mathematics

2 answers:

maksim [4K]3 years ago

7 0

Answer:

$CD=6\frac{2}{3}\ units$

Step-by-step explanation:

we know that

If rectangle ABCD is similar to rectangle ZBXY

then

the ratio of their corresponding sides is equal and is called the scale factor

$\frac{BC}{BX}=\frac{CD}{XY}$

in this problem we have

$BC=10\ units$

$BX=6\ units$

$XY=4\ units$

Substitute the values and solve for CD

$\frac{10}{6}=\frac{CD}{4}$

$CD=4*10/6$

$CD=20/3=6\frac{2}{3}\ units$

ololo11 [35]3 years ago

7 0

Answer:

cd=6 2/3 unis

Step-by-step explanation:

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Please Help!!!!! Ill give thanks and rate best!

Norma-Jean [14]

Answer:

1/216

1/8 *1/3³ ( cross multiply ) = 1/216

Did you only need the answer for the one on the top right?? Or all of them because If you need all of them I can do that too I am just assuming you just needed that one because it was selected.

4 0

3 years ago

pen costs twice as much as a pencil. The total cost of 1 1 pen and 1 1 pencil is $2.10 $ 2 . 10 . If p represents the cost of 1

dybincka [34]

Answer : The equation could you use to find p is, $2p+p=2.10$

Step-by-step explanation :

Let the cost of 1 pen be, 'x'

and the cost of 1 pencil is, 'p'

As we are given that total cost of 1 pen and 1 pencil is $2.10. The equation will be:

$x+p=2.10$ ............(1)

And we have also given that the pen costs twice as much as a pencil. The equation will be:

$x=2p$ ............(2)

Now put the equation 2 in equation 1, we get:

$x+p=2.10$

$2p+p=2.10$

Thus, the equation could you use to find p is, $2p+p=2.10$

3 0

3 years ago

Read 2 more answers

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

Speed of boat in still water $=14\ ms^-1$

Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

3 0

3 years ago

F(1) = 5

MatroZZZ [7]

Answer:

a(7)=3645

Step-by-step explanation:

you have :

f(1) =a= 5

and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)

So r=3

then

a(n)=a*r^(n-1)

a(7)=5*3^(7-1)

a(7)=5*3^6=3645

<em>hope this helps</em>

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7 0

2 years ago

Help me I want to understand this finnall part

allochka39001 [22]

6.7 x -2.3
You would multiply this just like any other multiplication question.
There is some work of course, but I'm not going to write it out here...
You are going to end up with -15.41, which is already rounded to the nearest hundredth.

Hope this helped :)

4 0

3 years ago

Read 2 more answers