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2 years ago

Find the value of y.

Mathematics

1 answer:

babunello [35]2 years ago

4 0

Answer:

y = 155

Step-by-step explanation:

6x + 1 = 2x + 17

x = 4

2 · 4 + 17 + y = 180

y = 155

I hope that this helps!!

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igomit [66]

Answer:

Step-by-step explanation:

6 0

2 years ago

Rewrite the expression -8(2+9v) using the distributive property

Ann [662]

Answer:

-16-72v

Step-by-step explanation:

-8*2 = -16

-8*9v = -72v

so, -16 + (-72v) -> -16-72v

7 0

2 years ago

Read 2 more answers

A number z, when rounded to the nearest whole, is equal to 70. Find the upper and lower bound of x

rusak2 [61]

Answer:

A quick way to calculate upper and lower bands is to halve the degree of accuracy specified, then add this to the rounded value for the upper bound and subtract it from the rounded value for the lower bound.

4 0

2 years ago

The difference of a number m and 18 how would you write a algebraic expression

Tpy6a [65]

Answer:

m - 18

Step-by-step explanation:

Symbolically, that difference would be written as m - 18.

6 0

2 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago