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The given equation is
From the given equation,
a = 40
b = 96
(h,k) = (0,0), the center
The vertices are at (0,96) and at (0, -96).
The curves open upward and downward.
c² = a² + b² = 40² + 96² = 10816
c = 104
Therefore the foci are at (0, -104) and (0, 104).
Check the given answers:
1. a focus at (104, 0) is INCORRECT
2. a focus at (0, -96) is INCORRECT
3. a vertex at (-40, 0) is INCORRECT
4. a vertex at (0, 96) is CORRECT
5. the center at (0, 0) is CORRECT
From the given equation,
a = 40
b = 96
(h,k) = (0,0), the center
The vertices are at (0,96) and at (0, -96).
The curves open upward and downward.
c² = a² + b² = 40² + 96² = 10816
c = 104
Therefore the foci are at (0, -104) and (0, 104).
Check the given answers:
1. a focus at (104, 0) is INCORRECT
2. a focus at (0, -96) is INCORRECT
3. a vertex at (-40, 0) is INCORRECT
4. a vertex at (0, 96) is CORRECT
5. the center at (0, 0) is CORRECT
The oblique asymptote is y = x
This is a slant asymptote
You can find this by performing polynomial long division. See the attached image for how to do the division. The quotient is the single "x" up at the very top. The remainder is -2 at the very bottom. The oblique asymptote is equal to the quotient.
This is a slant asymptote
You can find this by performing polynomial long division. See the attached image for how to do the division. The quotient is the single "x" up at the very top. The remainder is -2 at the very bottom. The oblique asymptote is equal to the quotient.