Answer:
12.5 Sq inches
Step-by-step explanation: 225 is the area and the formula for area is b*h (base times height) and from the problem, you can see that 18 inches is the height. In this case you would do 225/18 which gives you 12.5 sq inches.
Answer:
Step-by-step explanation:
the first one is:
x= 3
y= 2
the second one is:
x= -2
y= 8
Answer:

Or

Step-by-step explanation:
We want to find the angle which forms a y-coordinate of 
on the unit circle.
The y-coordinate on the unit circle is given by
.
This implies that 



Or

Answer:
your answer is 1
Step-by-step explanation:
you have to first distribute your 3 to the parentheses, which gives you (21-12) so you are then going to subtract 12 from 21. and you get 9. 9 divided by 9 equals 1 so your answer is 1.
(21-12)/9
9/9
1
Answer:
Step-by-step explanation:
The height of the triangle is 4
and the base is 8
Area of a triangle is BH/2
Therefore the area is 16