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swat32
2 years ago
13

A dress which sosts $180 is being sold at a discoundof 10% the amount of the discount is

Mathematics
1 answer:
Degger [83]2 years ago
3 0

Answer:

The discount is $18.

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(b)Newton has bought 12 dozen copies in Rs 4320. His expenditure to bring the copies
Alexeev081 [22]

Answer:

30%

Step-by-step explanation:

4320 - 288 = 4032

4032/12 =336 per copies

So, he sold them in 5760

5760 - 4032 = 1728

(1728/5760)*100 = 30%

8 0
2 years ago
A teacher has a bag of candy. If she gives every student in her class 4 pieces of candy, she is left with 48 pieces of candy. Ho
yawa3891 [41]
Well you can't actually find a number, but you can make an equation.
lets call the bag of candy x, and the number of students in the teachers class S.

she gives every student in her class 4 pieces, so to find that amount, we have to multiply the number of students in her class by 4, the pieces of candy. 4S

afterwards she has 48 pieces, which is the endpoint, x is the starting point because that's the amount of candy the teacher started with.

so your equation is x-4S=48, but the thing is, the question is looking for the amount of students she gave candy to, so we have to isolate S, or in easier words; put S on one side, and the numbers on the other.

so the equation is S=1/4x-12

6 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
by selling a cell phone for 2400rs a shopkeeper makes a profit of 25% what would be his profit percentage if it was 2040rs​
xxMikexx [17]

Answer:

6.25%

Step-by-step explanation:

We first begin by solving for the original price of the cell phone.

if 2400 = 125%

         x = 100%

By cross multplying, we get

125x = 2400 * 100

x = 240000/125

x = 1920rs

To find the profit percentage on the new sale price, we repeat another set of equations

100% = 1920

      x = 2040

1920x = 2040 * 100

x = 204000/1920

x = 106.25%

His new profit percentage is 6.25%

7 0
3 years ago
Find the radius, please help asap due tuesday
Varvara68 [4.7K]

Answer:

I can't see anything man but you could do it alright

3 0
2 years ago
Read 2 more answers
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