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Vilka [71]
2 years ago
10

PLZ HELP ITS DUEEE RNNNNN!!!!

Mathematics
1 answer:
Dimas [21]2 years ago
4 0

Answer:

answer that do not poru branly

Step-by-step explanation:

hahahaahahahahha

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If m ABC = 122°, and m<br> then m
ANTONII [103]

Answer:

m < DBC = 51

Step-by-step explanation:

Looking at the picture, we know <ABD and <DBC make up <ABC. Knowing this, we can set up an equation like so, plug in the known values, and solve to find m<DBC:

m

6 0
2 years ago
Which of the equations listed below are linear equations?
telo118 [61]

Answer:

iK ITS A TRICKY QUESTION ITS C THOUGH

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I need help with this math problem!
Lyrx [107]

Answer:

12?

Step-by-step explanation:

i might be wrong, but from what it looks like, it shows 3 sections and one is labeled 4.

8 0
3 years ago
Graph the set of points. which model is most appropriate for the set? (-6, -1)(-3, 2)(-1,4)(2,7)
lianna [129]
For this case, the first thing to do is to graph the following ordered pairs:
 (-6, -1)
 (-3, 2)
 (-1,4)
 (2,7)
 We observe that the graph is a linear function with the following equation:
 y = x + 5
 Note: see attached image.
 Answer:
 
The function that best represents the ordered pairs is:
 
y = x + 5

5 0
3 years ago
Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)
Paladinen [302]

Step-by-step explanation:

Let x represent theta.

\sin( \frac{\pi}{4} - x )

Using the angle addition trig formula,

\sin(x - y)  =  \sin(x)  \cos(y)  -  \cos(x)  \sin(y)

\sin( \frac{\pi}{4} )  \cos(x)  -  \cos( \frac{\pi}{4} )  \sin(x)

( \frac{ \sqrt{2} }{2})  \cos(x)  -  (\frac{ \sqrt{2} }{2}  )\sin(x)

Multiply one side at a time

Replace theta with x , the answer is

\frac{ \sqrt{2} \cos(x)  }{2}  -  \frac{ \sin(x) \sqrt{2}  }{2}

2. Convert 30 degrees into radian

\frac{30}{1}  \times  \frac{\pi}{180}  =  \frac{\pi}{6}

Using tangent formula,

\tan(x + y)  =  \frac{ \tan(x)  +  \tan(y) }{1 -  \tan(x) \tan(y)  }

\frac{ \tan(x) +  \tan( \frac{\pi}{6} )  }{1 -  \tan(x) \tan( \frac{\pi}{6} )  }

Tan if pi/6 is sqr root of 3/3

\frac{ \tan(x) +  ( \frac{ \sqrt{3} }{3} )  }{1 -  \tan(x)  (\frac{ \sqrt{3} }{3} )  }

Since my phone about to die if you later simplify that,

you'll get

\frac{(3 \tan(x) +  \sqrt{3} )(3 +  \sqrt{3}  \tan(x)  }{3(3 -  \tan {}^{2} (x) }

Replace theta with X.

4 0
2 years ago
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