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2 years ago

5a - {3b - 5[a - (b + -4a)]}

1 answer:

5 0

Interesting problem. When computers first came out (when dinosaurs ruled the planet), we had to deal with problems that were many brackets deep. So this has practical applications.

Start at the very right and keep on removing brackets and collecting like terms.

5a - {3b - 5[a - (b - 4a)]} I just changed the sign on the right bracket.
5a - {3b - 5[a - b + 4a]}
5a - {3b - 5[5a - b]} Now deal with []. You are still on the right.
5a - {3b - 25a + 5b}
5a - {8b - 25a} Finally remove {}
5a - 8b + 25a
30a - 8b
If you can solve another like this, you are well on your way to being good in computer science.

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1 year ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

1 year ago

Help this is due tomorrow

Helen [10]

-4.4(s - 2) + 6.9s = 14.8

Distribute -4.4 into the parenthesis:

-4.4s + 8.8 + 6.9s = 14.8

Combine like terms:
2.5s + 8.8 = 14.8

Subtract 8.8 from both sides of the equation:

2.5s + 8.8 - 8.8 = 14.8 - 8.8

2.5s = 6

Divide both sides by 2.5:

2.5s/2.5 = 6/2,5

s = 2.4

s =

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