Please help me I'm stuck on these questions!

Mathematics

1 answer:

defon2 years ago

8 0

5.) (part 1) is 5x^3, part 2 is 0.25x^2
6.) part 1.) D^2. Part 2.) T^2
7.) part 1.) x^9, part 2.) y^10
9.) part 1.) 15x^2y^3, part 2.) 5ab

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Use pi=3.14 to estimate the circumference of the circle to the nearest hundreth the diameter is 11 cm

TiliK225 [7]

The formula of circumference: 兀×diameter

In this case:

3.14×11
=34.54cm

Nearest hundreth = 2 demical places

Therefore, the answer is 34.54cm.

Hope it helps!

3 0

2 years ago

Explain why 2+x and x+3 are equivalent

wlad13 [49]

Check whether the two expressions 2x+3y2x+3y and 2y+3x2y+3x equivalent.

The first expression is the sum of 2x2x 's and 3y3y 's whereas the second one is the sum of 3x3x 's and 2y2y 's.

Let us evaluate the expressions for some values of xx and yy . Take x=0x=0 and y=1y=1 .

2(0)+3(1)=0+3=32(1)+3(0)=2+0=22(0)+3(1)=0+3=32(1)+3(0)=2+0=2

So, there is at least one pair of values of the variables for which the two expressions are not the same.

5 0

2 years ago

Aaron is reading a graph of equivalent ratios. If one of the ratios is represented as (6, 2), which could be another ratio?

evablogger [386]

There Are Unlimited Equivalent Ratios To This! For One, We Could Simplify This Ratio To 3,1.Another One Would Be 12,4. You See, It Can Be Any Ratio As Long As It Equals(Simplified) To 3/1. I Hope This Helps!

6 0

2 years ago

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A 25- foot long board is to be cut into two parts. the longer part is one foot more than twice the shorter part. how long is eac

satela [25.4K]

One part is 8 feet long and the other part is 17 feet long.
8+17=25
(8x2)+1=17

5 0

3 years ago

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An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.

bogdanovich [222]

1. Check the picture attached. Consider the half of the 8-sided die, that is the pyramid ABCDE:

2. The perimeter of the base is 6, so each side of the base is 6/4=3/2

3. The distance between the tallest points is 2 cm, si the height of Pyramid ABCDE is 1 cm.

4. Consider the right triangle EOM in the figure:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is $\sqrt{1+ ( \frac{3}{4} )^{2} }= \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4}$ (cm)

5. So side EBC has area
$\frac{1}{2}BC*EM= \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}$

6. The total area is 8*Area(EBC)= $8* \frac{15}{16}= \frac{15}{2}=7.5 ( cm^{2} )$

6 0

3 years ago

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