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Bas_tet [7]
3 years ago
12

I NEED HELPP!!!

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Sorry I can't help you :(

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Select the correct answer.<br><br> Which shape is similar to shape I?
Mkey [24]
The answer is B it’s the same shape just a small decrease in size
5 0
3 years ago
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Please answer thanks giving points for who helps:)
sashaice [31]

Answer:

graph A and graph C are proportional.

Step-by-step explanation:

both graph A and graph C start at the origin (0,0). graph B does not.

3 0
3 years ago
Which expressions are equivalent? Select two answers.
professor190 [17]

Answer:

<h2>A, C</h2>

Step-by-step explanation:

The distributive property:

<em>a(b + c) = ab + ac </em>or<em> a(b - c) = ab - ac</em>

<em></em>

A.\\\\\dfrac{1}{5}(x-50)=\dfrac{1}{5}x-\left(\dfrac{1}{5}\right)(50)=\dfrac{1}{5}x-\dfrac{50}{5}=\dfrac{1}{5}x-10\\\\B.\\\\-\dfrac{1}{3}(3x+18)=\left(-\dfrac{1}{3}\right)(3x)+\left(-\dfrac{1}{3}\right)(18)=-\dfrac{3}{3}x-\dfrac{18}{3}=-x-6\\\\-x-6\neq\dfrac{1}{3}x-6

C.\\\\\dfrac{1}{2}(x+16)=\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)(16)=\dfrac{1}{2}x+\dfrac{16}{2}=\dfrac{1}{2}x+8\\\\D.\\\\\dfrac{1}{8}(8x+8)=\left(\dfrac{1}{8}\right)(8x)+\left(\dfrac{1}{8}\right)(8)=\dfrac{8}{8}x+\dfrac{8}{8}=x+1\\\\x+1\neq\dfrac{1}{8}x+1\\\\E.\\\\-\dfrac{1}{4}(x+2)=-\dfrac{1}{4}x+\left(\dfrac{1}{4}\right)(2)=-\dfrac{1}{4}x+\dfrac{2\!\!\!\!\diagup^1}{4\!\!\!\!\!\diagup_2}=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\-\dfrac{1}{4}x+\dfrac{1}{2}\neq-\dfrac{1}{4}x+2

4 0
3 years ago
Evaluate the expression for the given value of x.<br> 3x + 4 for x= 5
pantera1 [17]
Answer:
19

Explanation:
3x+4
Plug in 5 as x
3(5)+4
=15+4
=19

I hope this helps!
7 0
3 years ago
What is the answer to this?
Katyanochek1 [597]
I think it's C, reflexive property.
8 0
3 years ago
Read 2 more answers
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