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Sloan [31]
3 years ago
11

In the first 8 overs the bowling rate of a cricketer is 4.5, In the last two over by giving how much run the bowling rate will b

e 5? ​
Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

In the last two overs, the bowler gave 14 runs.

Step-by-step explanation:

The bowling rate of 4.5 in the first 8 over means he gave 32.5 runs.

i.e.

Score given in first 8 overs = 4.5 × 8 = 36

Given that the bowling economy 5 at the end of 10 overs means the bowler must have given 10 × 5 = 50 score in the total 10 overs.

so, subtract 36 from 50 to get the score he will be giving in the last two overs.

i.e. score given the last two overs = 50 - 36 = 14

Therefore, in the last two overs, the bowler gave 14 runs.

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8 0
3 years ago
Read 2 more answers
A quantity, y, varies directly as x When y=10, x=6.<br> Find xwhen y= 14.
grigory [225]

The value of x when y = 14 is 8.4

<h3 />

<h3>How to solve variation ?</h3>

y, varies directly as x. Therefore,

y ∝ x

Therefore,

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Therefore,

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