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FrozenT [24]
3 years ago
14

Select the correct answer. Which shape is similar to shape I?

Mathematics
2 answers:
arsen [322]3 years ago
7 0
Answer: Shape 4 (D)
Mkey [24]3 years ago
5 0
The answer is B it’s the same shape just a small decrease in size
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Determine the solution by using substitution. Write your answer as a point below (x,y).
sladkih [1.3K]

Answer:

(2,-2)

Step-by-step explanation:

To solve this using substitution you would take your second equation and plug it in for y of the first equation (4x-10= -3x+4). You then would add the 10 over (4x= -3+14). Next you add the 3x over(7x=14). Finally divide both sides by 7, which should give you x=2. Now all you have to do is plug the two in for x in one of your equations (which ever equation you prefer) (y=-3(2)+4). Solve the equation and you will then have the answer to y, which you can then put into a point.

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U.S postal service regulations state that a package can be mailed using parcel post rates is it weighs no more that 70 pounds. W
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equation 5×12=60 any more would equal 72
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4 years ago
What is the equation of the line?
Ivahew [28]

Answer:

x=0

Step-by-step explanation:

The line is perpendicular to y axis and passes through origin. Thus it's x=0

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3 years ago
Find the diameter of a sphere with a surface area of 196π square centimeters
aleksandr82 [10.1K]

\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ SA=196\pi \end{cases}\implies \begin{array}{llll} 196\pi =4\pi r^2\implies \cfrac{196\pi }{4\pi }=r^2 \implies 49=r^2 \\\\\\ \sqrt{49}=r\implies 7=r~\hfill \underset{diameter}{\stackrel{2(7)}{14}} \end{array}

7 0
2 years ago
Consider h(x)=x^2+8+15. identify its vertex and y-intercept.
OleMash [197]

Answer:

Vertex: (-4, -1)

Y-intercept: (0, 15)

Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, [x = \frac{-b}{2a}, h(\frac{-b}{2a})].

<h3>Use the equation:  [x = \frac{-b}{2a}, h(\frac{-b}{2a})]</h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

x = \frac{-b}{2a}

x = \frac{-8}{2(1)}

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

h(-4) = (-4)² + 8(-4) + 15

h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

5 0
3 years ago
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