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Ber [7]
2 years ago
6

Solve the following 5 3/4 + (6 2/3 - 4 5/6) =

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
4 0

Answer:

7 5/12

Step-by-step explanation:

first, subtract 4 5/6 from 6 2/3 by converting 6 2/3 to 6 4/6

5 3/4 + (6 4/6 - 4 5/6) = 5 3/4 + 1 4/6

* I borrowed 6/6 or '1' from the 6 and made 4/6 into 10/6

5 3/4 equals 5 9/12 and 1 4/6 equals 1 8/12

adding them gives you:

6 17/12 which is the same as 6 + 1 5/12, or 7 5/12

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A rectangular plot of ground is 30 meters longer than it is wide. its area is 10,000 square meters.
dimulka [17.4K]
A = W· L
10,000 = W ( W +30 ) = W² + 30 W
W² + 30 W - 10,000 = 0
W = \frac{-30+ \sqrt{900+40000} }{2}=  \frac{-30+202.24}{2} = 86.12
L = 86.12 + 30 = 116.12
Width of a plot is 86.12 m and lenght is 116.12 m.
Check : A = 116.12 · 86.12 ≈ 10,000
6 0
3 years ago
Find the missing value to the nearest whole number. sin17∘=x/7
wlad13 [49]

Answer:

2

Step-by-step explanation:

sin 17° = x/7

(sin 17°) 7 = (x/7)7

x = sin 17° (7)

x = 0.292371704722737 (7)

x = 2.046601933059157

x ≈ 2

6 0
2 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
Tata Darka ma 20 m siatki ogrodzeniowej.Jakie wymiary w metrach,wyra¿one liczbami naturalnymi,powinien mieæ prostok¹tny warzywni
grin007 [14]

Answer:

Hence the dimensions are 5×5 i.e. 5 meters and 5 meters such that its field would be as large as possible.

Step-by-step explanation:

Darek's dad has a 20 m fencing mesh.

Since we have to make a rectangular garden with he help of fencing the garden using this mesh, that means perimeter of this garden is 20 m.

i.e. 2( l+b)=20

also we have to fenced in such a way that its field would be as large as possible.

ie. it has the largest Area.

Now we will start from the dimensions possible as:

9×1 whose area will 9 m^2 (since Area=l×b)

Next dimension will be:

8×2 whose area will be 16 m^2

Next will be:

7×3 whose area will be 21 m^2

Next will be:

6×4 whose area will be 24 m^2

Next will be:

5×5 whose area will be 25 m^2

Next will be:

4×6 whose area will be same as of 6×4.

Hence, we get the maximum area to be 25 m^2 which is obtained when the dimensions are 5×5.



5 0
3 years ago
What is the expression equivalent to xy ^ 2/9
DochEvi [55]

Answer:

hi someone help me too

Step-by-step explanation:

6 0
3 years ago
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