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I am Lyosha [343]
3 years ago
15

The percent of adults who smoke, recorded every few years since 1967, suggests a negative linear association with no outliers. A

line was fit to the data to model the relationship.
Which of these linear equations best describes the given model?
Choose 1 answer:
(Choice A)
A
y=-0.5x+40

(Choice B)
B
y=-x+40

(Choice C)
C
y=-2x+40

(Choice D)
D
y=-3x+40
​
Based on this equation, estimate what percent of adults smoked in 1997.
Round your answer to the nearest tenth of a percent.
Mathematics
2 answers:
earnstyle [38]3 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

scoray [572]3 years ago
3 0

Answer:the answer is a and it’s 25%

Step-by-step explanation:

You might be interested in
The first four terms of an arithmetic sequence are -11,-5,1,7. what is the equation for an
mr_godi [17]

Answer:

y = 6x - 11

Step-by-step explanation:

An arithmetic sequence is a linear function. This means it steadily increases or decreases through addition/subtraction by a constant amount. Here the sequence grows by adding 6 each time.

-11 + 6 = -5

-5 + 6 = 1

1 + 6 = 7

etc....

Since this is linear, its equation has the form y = mx + b where m is the slope and b is the y-intercept. The slope is m = 6 and b = -11.

y = 6x - 11

7 0
3 years ago
A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors
mezya [45]
<h3>Answer:  491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

  • 15 ways to pick the freshmen
  • 1287 ways to pick the sophomores
  • 70 ways to pick the juniors
  • 364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0
2 years ago
The table shows the solution to the equation |2x - 4| - 3 = 3:
dimaraw [331]

Answer:

Step 1

Step-by-step explanation:

Step one is incorrect because you need to add 3 but it subtracted.

8 0
4 years ago
Solve the equation: 14&lt;2x−1≤20
mafiozo [28]

Answer:

7.5 < x≤10.5

Step-by-step explanation:

14<2x−1≤20

Add 1 to all sides

14+1<2x−1+1≤20+1

15<2x≤21

Divide each side by 2

15/2 <2x/2 ≤21/2

7.5 < x≤10.5

5 0
3 years ago
Read 2 more answers
HELP PLEASE HELP I BEG YOU lol
Butoxors [25]
B. because the oval and the quad are there naturally

C. Because the 1.25 intrest makes sense with the 6.50 amount
4 0
3 years ago
Read 2 more answers
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