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Nutka1998 [239]
2 years ago
10

Soccer players are expected to congratulate and shake hands with the opponent team, even when their team loses the game. This be

st exemplifies
Mathematics
1 answer:
maksim [4K]2 years ago
3 0

A good game spirit must be shown between opponent <u>teams</u> when playing <em>soccer</em>. Thus, to <u>congratulate</u> and <u>shake</u> hands is an example of a display rule.

<u>Soccer</u> players sometimes i<em>njure</em> one another during a game, or can engage in an act which can lead to an <em>offence</em> on the other part. These does not make the players to be <em>enemies</em>.

The game requires a <em>fair</em> play and <em>good game</em> spirit among players no matter the <em>outcome</em> (result) of the game. Thus it is one of the rules, though not <u>mandatory</u>, for soccer players to <em>congratulate</em> one another or <em>shake</em> hands.

This best exemplifies a display rule which implies that either of the team winning or losing a game does not turn opponent team to an <u>enemy</u>. This act is displayed especially after a game without any <em>hindrance</em> to it.

Visit: brainly.com/question/23369457

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Near the beginning of Lesson 5.3, a strategy for factoring trinomials of the form x^2+ bx+c was
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Answer:

Step-by-step explanation:

there are function that "invert" each other..

subtraction inverts addition...

3+2 = 5 ... 5-2 = 3

division inverts multiplication

5*2 = 10 ... 10/2 = 5

Using that concept, "factoring" is basically the inverse of multiplication

3x^2 + 9x can be factored to 3x(x+3)

if you multiply that out it reverts back to the original equation

so  x^2 + 5x + 6 factors to (x+3)(x+2)

if you multiply that out (foil it)

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3 years ago
What is 2.764 rounded to the nearest hundredth
kifflom [539]

Answer:

2.76

Step-by-step explanation:

you only round up if it is a five or higher

8 0
3 years ago
Read 2 more answers
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
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Answer: I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }

Step-by-step explanation:

Given the data in the question;

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so 'V' is in the span if;

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V =    [ 6si + 5sj ] + [ 6tj + 5tz]

V = 6s, 5s+6t, 5t

so

I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }

5 0
3 years ago
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