Please solve this math problem... I will mark you brainliest
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The vertices of ABCD after 90 degrees clockwise rotation about point C are: A' (0,6), B' (3,7), C' (4,6) and D' (4,3)
<h3>How to match the vertices of the polygon?</h3>The image of the polygon ABCD is not given; however, the question can still be answered because the coordinates are known.
The vertices of polygon ABCD are given as:
A = (4, 6)
B = (5, 3)
C = (4, 2)
D = (1, 2)
The rule of rotation about point C is:
(x,y) = (a + b - y, x + b - a)
Where:
(a, b) = (4, 2) --- the point of rotation.
So, we have:
(x,y) = (4 + 2 - y, x + 4 - 2)
(x,y) = (6 - y, x + 2)
The above means that:
A' = (6 - 6, 4 + 2) = (0,6)
B' = (6 - 3, 5 + 2) = (3,7)
C' = (6 - 2, 4 + 2) = (4,6)
D' = (6 - 2, 1 + 2) = (4,3)
Hence, the image of the rotation and their vertices (i.e. coordinates) are:
A' = (0,6)
B' = (3,7)
C' = (4,6)
D' = (4,3)
Read more about rotation at:
#SPJ1
The formula for the surface area of a cylinder is:
2<span>π</span><span>r</span><span>h </span><span>+ </span><span>2</span><span>π</span><span>r^</span><span>2
If we substitute in the measurements that we know, you get:
2</span><span>
(3.5) (14) + 2</span><span> (3.5)^2
If we simplify this expression, we get:
98</span><span> + 24.5</span><span>
If you simplify once more, you get
122.5</span><span> or </span><span>≈ 384.85
Therefore, the surface area is 122.5</span> or about 384.85<span>
</span>
2<span>π</span><span>r</span><span>h </span><span>+ </span><span>2</span><span>π</span><span>r^</span><span>2
If we substitute in the measurements that we know, you get:
2</span><span>
If we simplify this expression, we get:
98</span><span>
If you simplify once more, you get
122.5</span><span>
Therefore, the surface area is 122.5</span>
</span>