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NISA [10]
2 years ago
5

Multi-Select Technology-Enhanced

Mathematics
1 answer:
larisa86 [58]2 years ago
8 0

Answer:

1,6

-5,9

2,3

Step-by-step explanation:

You might be interested in
which of the following rational functions is graphed below. A.F(x)=1/x(x+2) B. F(x)=2x/x(x-2) C.F(x)=2x/x(x-2) D. F(x)=(x+1)/(x+
nexus9112 [7]

Answer:

you don't have the graph

Step-by-step explanation:

3 0
2 years ago
Someone please help me with these Geometry questions.
AnnZ [28]
<h3>Answer: 112.5 square units</h3>

Work Shown:

A = area of the triangle

A = base*height/2

A = 9*7/2 = 63/2 = 31.5 ... see note1 below

B = area of rectangle

B = base*height

B = 9*3 = 27

C = area of parallelogram

C = base*height .... see note2 below

C = 9*6 = 54

If you're confused where I got the 6 from, check out the attached image below.

D = total area of the composite figure

D = A+B+C

D = 31.5 + 27 + 54

D = 112.5

-------------------------

note1: The vertical component of the triangle is 9 units because this is part of the rectangle. The rectangle has opposite sides that are the same length. The parallelogram's vertical sides are 9 units long as shown by the single tickmark.

note2: a rectangle is essentially a special case of a parallelogram. In other words, a rectangle is a parallelogram with 4 right angles. So this is why the formula "area = base*height" shows up identical for both rectangles and parallelograms. Keep in mind that the height is always perpendicular to the base. You will not use the segments marked with double tickmarks.

6 0
3 years ago
What is the value of x?
mariarad [96]
It would be 11 because you would add the x's and divide it by 55. 55/5=11
3 0
3 years ago
Read 2 more answers
Reduce -2+b2 by 7+b2
svlad2 [7]
I think the answer is -9.
4 0
2 years ago
Use trigonometric identities to solve each equation within the given domain.
KengaRu [80]

It looks like the equation is

-sin²(<em>x</em>) = cos(2<em>x</em>)

Recall the half-angle identity for sine:

sin²(<em>x</em>) = (1 - cos(2<em>x</em>))/2

Then the equation can be written as

-(1 - cos(2<em>x</em>))/2 = cos(2<em>x</em>)

Solve for cos(2<em>x</em>):

-1/2 + 1/2 cos(2<em>x</em>) = cos(2<em>x</em>)

-1/2 = 1/2 cos(2<em>x</em>)

cos(2<em>x</em>) = -1

On the unit circle, cos(<em>y</em>) = -1 when <em>y</em> = arccos(-1) = <em>π</em>. Since cosine has a period of 2<em>π</em>, more generally we have cos(<em>y</em>) = -1 for <em>y</em> = <em>π</em> + 2<em>nπ</em> where <em>n</em> is any integer. Then

2<em>x</em> = <em>π</em> + 2<em>nπ</em>

<em>x</em> = <em>π</em>/2 + <em>nπ</em>

<em />

In the interval [-<em>π</em>, <em>π</em>], you get two solutions <em>x</em> = -<em>π</em>/2 and <em>x</em> = <em>π</em>/2.

8 0
2 years ago
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