H ( x ) = - 6 + x
m = 1 ( the slope )
b = - 6 ( y - intercept )
x - intercept:
0 = - 6 + x
x = 6
The graph is going through Quadrants: I, II and IV.
Answer:
B ) Quadrant II, because the slope is positive and y-intercept is negative.
Answer:
it might be D
Step-by-step explanation:
im pretty sure
Answer:
+ 3x³ - 16x² + 27x - 18
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
x²(4x² - 5x + 6) + 2x(4x² - 5x + 6) - 3(4x² - 5x + 6)
Distribute all 3 parenthesis
= 4 - 5x³ + 6x² + 8x³ - 10x² + 12x - 12x² + 15x - 18
Collecting like terms
= 4 + 3x³ - 16x² + 27x - 18
Answer:
15
Step-by-step explanation:
the common ratio is 1/2 so you do 30(1/2)
30(1/2)=15
Hello! Lets solve this :)
So for the first question :
h(t) = -16t^2 + 150
h(0)= -16 (0)^2 + 150
h(0)= -16(0) + 150
h(0)= 0 + 150
h(0)= 150 feet
Second question
We need to find here the time when the ball hit the ground; or when the height h(t) is 0.
In equation form
h(t) --> 0=16t^2 + 150
16t^2 = 150
t^2=150/16
t= <span>√150/16
t= 5</span><span>√6/4
t= 5 (2.45)/4
t= 3.06 seconds
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Hope this helps! If you have any other questions or would like further explanation just let me know! :)
