A tank pumps out liquid at a rate of 12 gallons every 20 days. What is the unit rate in gallons per week?

Lee wants to cut this piece of canvas into two rectangles that are 3×2 and 3×5. He wants the sum of the areas of the two small r

scoray [572]

First find the area of the large rectangle which is 90 by you times 3 and 3 which is 9 then you times 5 and 2 which is 10 after that u times 9 and 10 which is 90 So to make the small rectangle times 6 and 15 because 3 times 2 equals 6 and 5 times 3 equals 10 so that means the area of one small rectangle is 6 and the other rectangle us 15 then u multiple

6 0

3 years ago

One serving of the food product contains 1g total saturated fat or 5% daily value (DV) for saturated fat. What is the daily valu

Leona [35]

Answer:

The daily value for saturated fat is 20g.

Step-by-step explanation:

Percentage problems can be solved by rule of three

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

A percentage problem is an example where the relationship between the measures is direct.

The problem states that 1g is 5% of the daily value for saturated fat. The daily value(100%) for saturated fat is x, so:

1g - 5%

xg - 100%

5x = 100

$x = \frac{100}{5}$

x = 20g

The daily value for saturated fat is 20g.

6 0

3 years ago

At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening

pav-90 [236]

Answer:

$z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4$

$p_v =2*P(z>4)=0.0000633$

When we compare the significance level $\alpha=0.1$ we see that $p_v$ so we can reject the null hypothesis at 10% of significance. So the the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation

$\bar X=23$ represent the sample mean

$\sigma=3.5$ represent the population standard deviation

$n=49$ sample size

$\mu_o =21$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:

Null hypothesis: $\mu = 21$

Alternative hypothesis: $\mu \neq 21$

The statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(z>4)=0.0000633$

Conclusion

When we compare the significance level $\alpha=0.1$ we see that $p_v$ so we can reject the null hypothesis at 10% of significance. So the the true mean is difference from 21 at this significance level.

8 0

3 years ago

Round to the underlined place

DENIUS [597]

Answer:

i think it would be 75.40

Step-by-step explanation:

The 6 would bring the 3 up one.

5 0

3 years ago

Read 2 more answers

PLEASE HELP!! // True Or False ?

Nataliya [291]

Answer:

1. TRUE

2. False

3. TRUE

4. False

5. TRUE

6. False

Step-by-step explanation:

1. 6859^(1/3) = 19 = ∛(19^3)

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2. 2197^(1/3) = 13 ≠ 9·2

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3. 8000^(1/3) = 20 = 10·2

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4. 9261^(1/3) = 21 ≠ 13

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5. 3375^(1/3) = 15 = 5·3

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6. 5832^(1/3) = 18 ≠ 3·7

7 0

3 years ago

Read 2 more answers