1 foot is about 0,3 meters.
If the height of the cabbage palmetto is 80 feet, it should be about 80*0,3 = 24 meters.
So a cabbage palmetto with 80 feet of height is about 24 meters.
Hope this helps! :)
Answer:
A is the answer I go with although Im not that sure
Answer:
1, 2, 3
Step-by-step explanation:
X <= 20 means that x has to be less than OR equal to 20.
The first option is -100. That's less than 20, so this statement is true.
The second option is 10. That's also less than 20, so this statement is also true.
The third option is 20. This is equal to 20, so this is also true.
The fourth option is 21, which is greater than 20, so it's not true.
The fifth option is 45, which is greater than 20, so it's not true.
Sorry I answered so late, hope this helps even though you probably don't need it anymore.
Question:
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds. Write an equation to determine how long it will take for the ball to reach the ground.
Answer:

Step-by-step explanation:
Given

Required
Find t when the ball hits the ground
This implies that h(t) = 0
So, we have:

Reorder

Using quadratic formula, we have:

Where

So, we have:




This gives:
or 
or 
or 
But time can not be negative.
So, we have:


<em>Hence, time to hit the ground is 5.0625 seconds</em>