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user100 [1]
3 years ago
6

Which is the best way to fix the following run on sentence

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

C

Reasoning:

You should add a period to fix the run-on sentence because they're two different ideas. (They don't fit in the same sentence.)

You might be interested in
An angle measures 74° less than the measure of its supplementary angle. What is the measure of each angle?
Olin [163]

Given that the two angles are supplementary, the measure of each angle is 127° and 53°.

<h3>What is the measure of each angle?</h3>

Supplementary angles are two angles whose sum is 180 degrees.

Given the data in the question, let 'x' represent the measure of the first angle.

  • Measure of first angle = x
  • Measure of second angle = x - 74
  • Sum of the complementary angles = 180°

Since supplementary angles are two angles whose sum is 180 degrees.

Measure of first angle + Measure of second angle = 180

x + ( x - 74 ) = 180

x + x - 74 = 180

2x - 74 = 180

2x = 180 + 74

2x = 254

x = 254/2

x = 127°

Hence,

Measure of first angle = x = 127°

Measure of second angle = x - 74 = 127 - 74 = 53°

Given that the two angles are supplementary, the measure of each angle is 127° and 53°.

Learn more about supplementary angles brainly.com/question/23582576

#SPJ1

5 0
2 years ago
The radius of a circle is 9 ft. Find the circumference \textit{to the nearest tenth}to the nearest tenth.
Veseljchak [2.6K]

Answer:

56.55 ft.

Step-by-step explanation:

Circumference

2\pi  r

For this case:

r = 9

Thus:

2\pi(9) = 56.5486...

rounded to the nearest tenth we have

C = 56.55 ft.

5 0
3 years ago
Plz help mee ;-; .................
forsale [732]
4X+60=640
4X=640-60
4X=580
X=580/4=145
8 0
3 years ago
Courtney and Alan are conducting an experiment. Every time Courtney flips a fair two-sided coin, Alan rolls a six-sided die. Wha
Naily [24]

Answer:

I think the answer is D. 1/12

7 0
3 years ago
Read 2 more answers
Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive
PtichkaEL [24]
Looks like the PMF is supposed to be

\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65

Next,

\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25

\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5

\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2
\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5
\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}

If Y=X^2+1, then X^2=Y-1\implies X=\sqrt{Y-1}, where we take the positive root because we know X can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that Y can take on the values 1^2+1=2, 2^2+1=5, and 5^2+1=26. At these values of Y, we would have the same probability as we did for the respective value of X. That is,

\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}

Part (5) is incomplete, so I'll stop here.
8 0
3 years ago
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