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Bond [772]
3 years ago
12

If 2a/ b = 1/ 2 , what is the value of b a ? A)

Mathematics
1 answer:
elena55 [62]3 years ago
7 0

Not enough information.

You've got one equation with two variables. There are an infinite number of answers.

Any pair of numbers works, just as long as b is 4 times the size of a .

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Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru
jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time (t_{T}) that Keenan will be from home is the sum of run (t_{R}), hang out (t_{H}) and walk times (t_{W}), measured in hours:

t_{T} = t_{R}+t_{H}+t_{W}

If Keenan runs and walks at constant speed, then equation above can be expanded:

t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}

Where:

x_{R}, x_{W} - Run and walk distances, measured in miles.

v_{R}, v_{W} - Run and walk speeds, measured in miles per hour.

Given that x_{R}=x_{W} = 2.5\,mi, v_{R} = 6\,\frac{mi}{h}, v_{W} = 4\,\frac{mi}{h} and t_{H} = 0.75\,h, the total time is:

t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }

t_{T} = 1.792\,h (1\,h\,48\,m)

Kennan will be from home approximately an hour and 48 minutes.

7 0
3 years ago
I need help with this
defon

i guess just times them all then divide up by how many numbers you have

3 0
3 years ago
Help me please no coin thots I will report please explain your answer
Leokris [45]
Should be equal to. sorry if its incorrect, but that's what i would go with.

7 0
3 years ago
Read 2 more answers
Which statement describes ?
Deffense [45]

Answer: B

The series converges because it has a sum of 4.

Step-by-step explanation:

8 0
3 years ago
A test of abstract reasoning is given to a random sample of students before and after they completed a formal logic course. The
Natasha_Volkova [10]

Answer:

The right answer is "0.2".

Step-by-step explanation:

The given values are:

\bar{x_0} = 3.7

s_o=4.95

t_{\frac{0.05}{2} }=2.2621

As we know,

95% confidence for \mu_0 will be:

= \bar{x_0} \pm t_{\frac{0.05}{2} },n-1\times \frac{s_o}{\sqrt{n} }

The lower bound will be:

= 3.7-2.2621\times \frac{4.95}{\sqrt{10} }

= 0.16\simeq 0.2

The upper bound will be:

= 3.7+2.2621\times \frac{4.95}{\sqrt{10} }

= 7.23\simeq7.2

Thus the right answer is "0.2"

8 0
3 years ago
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