Question

What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97. 6˚c) and 1 atm? please report your answer two points past the decimal with the unit j/molk. ∆h˚fus = 3. 17 kj/mol.

Answer 1

Answer:

the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

Explanation:

Entropy is defined as the measure of possible arrangement of the atoms or molecules. Entropy change for the the freezing process mole of 1 liquid methanol at -97.6 degree celcius and 1 atm will be -18.07 J/mol.

The entropy change can be calculated by the given formula:

 

Thus, the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

(Hope this helps can I pls have brainlist (crown)☺️)