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Degger [83]
3 years ago
10

Please I need help with this

Mathematics
2 answers:
Firdavs [7]3 years ago
7 0

Answer:

I can help, but what is the equation?

dolphi86 [110]3 years ago
7 0
662828288282838282838383
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5x+15y=75 WRITE Equation in Standard Form
sergeinik [125]

Answer:

15y=-1/3x+5

Step-by-step explanation:

-5x15y=-5x+75

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2 years ago
ANSWER PLZ QUICK AND FAST
Sergio [31]

Jack had b boxes. Then he got 4 more. That is equal to:

b+4

On Wednesday, half the boxes were destroyed. To find half the amount, you can divide by 2, which is equal to:

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Choice C matches the answer. Your answer is C

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A student was asked to use the formula for the perimeter of a rectangle, p = 2l 2w, to solve for l. the student came up with an
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3 years ago
Choose the phrase that best describes the matrix
lions [1.4K]

Answer:

coefficent matrix

Step-by-step explanation:

P. 366

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7 0
3 years ago
Read 2 more answers
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
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