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2 years ago

13

−1.5(4−n)+2.8 simplified is???

1 answer:

ella [17]2 years ago

4 0

Answer: No

Step-by-step explanation:

You have to do the Distributive Property.

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Please select the best answer from the choices provided<br><br> A<br> B<br> C<br> D

SSSSS [86.1K]

ANSWER

The correct answer is D.

$\sum_{n=1} ^{6} (n - 3) = ( - 2) + ( - 1) + (0) + (1) + (2) + (3) = 3$

EXPLANATION

The given expression is

$\sum_{n=1} ^{6} (n - 3)$

The symbol means summation.

So we need to substitute

$n=1,n=2,n=3,n=4,n=5, \:and\:n=6$

into the formula and add all to get,

$\sum_{n=1} ^{6} (n - 3) = (1 - 3) + (2 - 3) + (3- 3) + (4 - 3) + (5 - 3) + (6 - 3)$

We simplify to obtain,

$\sum_{n=1} ^{6} (n - 3) = ( - 2) + ( - 1) + (0) + (1) + (2) + (3) = 3$

The correct answer is D

6 0

3 years ago

Read 2 more answers

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

brainly.com/question/24179531

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4 0

1 year ago

If you were given the points (6, -12) and (6, -4) could you find the slope of the line passing through them? why or why not?

GrogVix [38]

You could using your slope formula of rise/run, or (y2-y1)/(x2-x1)

8 0

3 years ago

Read 2 more answers

Which graph represents the function of f(x) = the quantity of 9 x squared plus 9 x minus 18, all over 3 x plus 6

lora16 [44]

Answer:

The answer is the option C

graph of $3x$ minus $3$ , with discontinuity at negative $2$ , negative $9$

Step-by-step explanation:

we have

$f(x)=\frac{9x^{2}+9x-18}{3x+6}$

Simplify

$f(x)=9\frac{(x^{2}+x-2)}{3(x+2)}$

$f(x)=3\frac{(x^{2}+x-2)}{(x+2)}$

Step 1

Convert to a factored form the numerator

$x^{2}+x-2=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+x=2$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+x+0.25=2+0.25$

$x^{2}+x+0.25=2.25$

Rewrite as perfect squares

$(x+0.5)^{2}=2.25$

Square root both sides

$x+0.5=(+/-)1.5$

$x=-0.5(+/-)1.5$

$x=-0.5+1.5=1$

$x=-0.5-1.5=-2$

so

$x^{2}+x-2=(x-1)(x+2)$

Step 2

Simplify the function f(x)

$f(x)=3\frac{(x^{2}+x-2)}{(x+2)}=3\frac{(x-1)(x+2)}{(x+2)}$

The domain of the function f(x) is all real numbers except the number $x=-2$

Because the denominator can not be zero

$f(x)=3\frac{(x-1)(x+2)}{(x+2)}=3(x-1)=3x-3$

$f(x)=3x-3$ ------> with a discontinuity at $x=-2$

$f(-2)=3(-2)-3=-9$

The discontinuity is at point $(-2,-9)$

the answer in the attached figure

8 0

3 years ago

Read 2 more answers

Simplify (1 - sin x)(1 + sin x).<br> 0 1<br> O cos^2 x<br> O sin^2 x<br> O tan^2 x

V125BC [204]

This would be cos^2x, because when you foil out the equation you get 1-sin^2(x).

1-sin^2(x)=cos^2(x)

5 0

3 years ago