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andre [41]
3 years ago
5

Solve this I don't understand this

Mathematics
1 answer:
Furkat [3]3 years ago
8 0
(16-x)/4 = (2x+2)/9
9(16-x) =  4(2x+2)
144 - 9x = 8x + 8
8x + 9x = 144 - 8
17x = 136
    x = 136/17
    x = 8

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nalin [4]

Answer:

40%

Step-by-step explanation:

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Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

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\vec a_1=,\ \vec a2=,\ \vec b=

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Multiplying both scalars by the vectors

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Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

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Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

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8 0
3 years ago
Jason has 1/6 yard of wire . He cuts it into 4 pieces of same length.what is the length in yards of each piece.
klemol [59]

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marin [14]

Answer:

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Step-by-step explanation:

When you graph the given equation on the given graph, you find the lines intersect at (-8, -6).

The solution to the system is (-8, -6).

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The equation is given in slope-intercept form, so you can find the y-intercept (y=10) and draw a line with slope 2 from there. It will go through (-5, 0), so you know the solution lies in the 3rd quadrant and has an x-value less than -5. Only one answer choice matches.

5 0
3 years ago
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I need HELPPPP I'll mark you the brainliest!
maksim [4K]

B, x = 2

Step-by-step explanation:

Given the vertices of the image, and preimage of this right isosceles triangle, we can find the line of reflection by definitively understanding how reflections work. Given the preimage contains the points A(-1,1), B(1,-1), and C(-3,-1). And that the image contains the points A'(5,1), B'(3,-1), C'(7,-1). We can differentiate the corresponding points and apply them to the rules of a reflection. if figure Z is reflected over x = n,

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we can prove this by using another point:

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Hopefully you understand,

<u>Pls mark brainliest this took me a very long time.</u>

3 0
3 years ago
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