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2 answers:
Answer:
No, this matrix is singular
Step-by-step explanation:
-1*-2*3=6
2*1*-2=-4
1*2*-1=-2
So, 6+(-4)+(-2)=0 -SINGULAR-
Answer:
Step-by-step explanation:
If determinant ≠ 0, then it is a non-singular matrix
<h2>Determinant = a₁(b₂c₃ -b₃c₂) - b₁(a₂c₃-a₃c₂)+c₁(a₂b₃-a₃b₂)</h2><h2>= 1(3-4) - 2(6 - 2) + (-1)(-4+ 1)</h2><h2>= 1*(-1) - 2*4 + (-1)*(-1)</h2><h2>= -1 - 8 + 1</h2><h2>= -8 </h2><h2>So, it is a non singular matrix</h2>
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