Question

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Answer 1

Answer:

No, this matrix is singular

Step-by-step explanation:

-1*-2*3=6

2*1*-2=-4

1*2*-1=-2

So, 6+(-4)+(-2)=0       -SINGULAR-

Answer 2

Answer:

Step-by-step explanation:

If determinant ≠ 0, then it is a non-singular matrix

Determinant =  a₁(b₂c₃ -b₃c₂) - b₁(a₂c₃-a₃c₂)+c₁(a₂b₃-a₃b₂)

= 1(3-4) - 2(6 - 2) + (-1)(-4+ 1)

= 1*(-1) - 2*4 + (-1)*(-1)

= -1  - 8 + 1

= -8

So, it is a non singular matrix