------»Kindly Don't espam!!⟵(o_O)

Question

ICE Princess25 [194]

2 years ago

11

------»Kindly Don't espam!!⟵(o_O)

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Mathematics

2 answers:

muminat · Answer 1 · 2023-02-02T21:31:56+03:00

muminat2 years ago

7 0

Answer:

No, this matrix is singular

Step-by-step explanation:

-1*-2*3=6

2*1*-2=-4

1*2*-1=-2

So, 6+(-4)+(-2)=0 -SINGULAR-

Inessa05 [86] · Answer 2 · 2023-02-02T23:56:13+03:00

Answer:

Step-by-step explanation:

If determinant ≠ 0, then it is a non-singular matrix

<h2>Determinant = a₁(b₂c₃ -b₃c₂) - b₁(a₂c₃-a₃c₂)+c₁(a₂b₃-a₃b₂)</h2><h2>= 1(3-4) - 2(6 - 2) + (-1)(-4+ 1)</h2><h2>= 1*(-1) - 2*4 + (-1)*(-1)</h2><h2>= -1 - 8 + 1</h2><h2>= -8 </h2><h2>So, it is a non singular matrix</h2>