Solve pls brainliest

Although companies would like consumers to believe that Identity theft protection is an

stiks02 [169]

The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is $\bar x =\frac{1}{n} \sum X_i$ where n is the number of observations; $X_i$ are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is $\bar x = \frac{1}{N}\sum f_ix_i$ where $N =\sum f_i$ and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is $m_e = 14.99$ , and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations $x_i$ and frequencies $f_i$ .

Then, the mean is calculated by

$\bar x = \frac{1}{N}\sum f_ix_i$

Where $N =\sum f_i$ (Sum of frequencies)

The median is calculated by

$m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.$

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

$\bar x =\frac{1}{n} \sum X_i$

Where n = 25; $X_i$ - n observations

On substituting,

Mean $\bar x$

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

$\bar x = \frac{1}{N}\sum f_ix_i$

Where N = 25;

On substituting,

$\bar x$ <em> </em>= 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

= 1/25 (402.42)

= 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So, the median $m_e$ = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

Learn more about frequency distribution here:

brainly.com/question/27820465

#SPJ9

7 0

2 years ago

Pls help quick! I am not sure if i did this right

bogdanovich [222]

Answer: The last option, <u>28</u> minutes

Step-by-step explanation:

See attached for my work. <em>If you are color blind let me know, I color-coded where I "pulled" numbers from.</em>

To answer this problem, we can look at the graph. We need to see for how long the black line is above the blue.

7 0

2 years ago

Read 2 more answers

The radioactive substance cesium-137 has a half-life of

statuscvo [17]

A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.

7 0

3 years ago

Tom knows that in his school 10 out of every 80 students are left-handed. There are 384 students in toms school. How many studen

Vika [28.1K]

Answer:

C (48)

explanation:

firstly, divide 384 by 80. This gives you 4.8. So, since 10 out of every 80 students are left handed we have to times 4.8 by 10 which gives you 48.

4 0

3 years ago

A container is filled with 100 grams of bird feed that is 80% seed. Tom and Sally want to mix the 100 grams with bird feed that

marta [7]

Answer:

Initially, we had:

100 grams of a mixture that is 80% seed, (or 0.8 in decimal form)

This means that the quotient between the mass of seeds and the total mass of the mixture is equal to 0.8

Then the mass of seeds, x, can be calculated as:

x/100g = 0.8

x = 0.8*100g

x = 80g

We also have another mixture, that is 5% seed (or 0.05 in decimal form)

This means that in X grams of this mixture, there will be y grams of seeds, such that:

y/X = 0.05

y = 0.05*X grams

Now, we want to create a mixture that is 40% seeds (or 0.4 in decimal form).

Let's do this.

If we add X grams of the 5% mixture, the total mass will be:

M = 100g + X.

The total mass of seeds will be:

m = 80g + X*0.05

and we want that the quotient between the mass of seeds and the total mass to be exactly 0.4

m/M = 0.4

(80g + X*0.05)/(100g + X) = 0.4

Let's solve this for X.

(80g + X*0.05) = 0.4*(100g + X)

80g + X*0.05 = 40g + X*0.4

80g - 40g = X*0.4 - X*0.05

40g = X*0.35

40g/0.35 = X = 114.2g

If we want the mixture to be exactly 40% seeds, we need to add 114.2g of the 5% mixture. (We already can see that Tom is closer to the exact result than Sally)

If we add 114g, like Tom wants, we will have:

M = 100g + 114g = 214g

m = 80g + 0.05*114g = 85.7g

m/M = 85.7g/214g = 0.4005

This is a really good aproximation, if we write this in percentage form this would be:

0.4005*100% = 40.05%

8 0

3 years ago