Answer:
the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Step-by-step explanation:
Since each bit is independent from the others , then the random variable X= number of 0 s in the code word follows a binomial distribution, where
p(X)= n!/((n-x)!*x!*p^x*(1-p)^(n-x)
where
n= number of independent bits=5
x= number of 0 s
p= probability that a bit is 0 = 0.8
then for x=1
p(1) = n*p*(1-p)^(n-1) = 5*0.8*0.2^4 = 0.0064 (0.64%)
therefore the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Answer: 21
Step-by-step explanation:
This means we can substitute x=5 into f(x), so f(5)=6+3(5)=21.
The true statement is that Stephen's factored expression is incorrect.
Given
The expression is given as:

<h3>What is factorization?</h3>
Factorization involves splitting a function into factors.
Start by expanding the equation

Factorize the equation

Factor out x - 7

Hence, the true statement is that Stephen's factored expression is incorrect.
Read more about factored expressions at:
brainly.com/question/11579257
The answer is A each country's economy!
6n^-3n-2 i think , have a good day!!