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Maslowich
2 years ago
6

#Quality answer needed #No spam _/|\_​

Mathematics
2 answers:
Rina8888 [55]2 years ago
7 0

Answer:

<h2><em><u>5.71</u></em><em><u>%</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

Cost price of the car when Arjun bought = ₹ 3,50,000

Cost price of that same car after 1 year = ₹ 3,70,000

<em><u>So</u></em><em><u>,</u></em>

Amount of money increased on the car's price

= ₹ (3,70,000 - 3,50,000)

= ₹ 20,000

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Percentage of increase on the car's price

=  \frac{20000}{350000}  \times 100

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=  \frac{2}{35}  \times 100

  • <em>[</em><em>On</em><em> </em><em>further</em><em> </em><em>Simplification</em><em>]</em>

= 5.7142......

= 5.71 (approx.)

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Percentage</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>increase</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>car's</u></em><em><u> </u></em><em><u>price</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>5.71</u></em><em><u>%</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

Svet_ta [14]2 years ago
3 0

Answer:

Price of car previous year = ₹3,50,000

Price of car next year = ₹3,70,000

Increase in price = ₹3,70,000–₹3,50,000

= ₹20,000

for,

Percentage of increase in price =

=  \frac{increase \: in \: price \: }{initiall \: price \: of \: car} \times 100  \\  =  \frac{20000}{350000}  \times 100 \\  \\  =  \frac{2}{35}  \times 100 \\  \\  =  \frac{200}{35}  \\  \\  =  > 5.7142 \:   =  > 5.72\%

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Montoya Construction needs to borrow $375,000 to build a road to install utilities in a small subdivision. It borrows the funds
MissTica

Step 1

Given;

\begin{gathered} \text{Principal(p)= \$375000} \\ \text{First rate = 8\%=}\frac{8}{100}=0.08 \\ \text{Second rate = 20\%= }\frac{20}{100}=0.2 \\ \text{Time}=\frac{90}{365}=\frac{18}{73} \end{gathered}

Required; To find the difference in interest between the two periods.

Step 2

State the formula for simple interest

A=P(1+rt)

Step 3

Find the interest when the rate is 8%

\begin{gathered} A=375000(1+(0.08\times\frac{18}{73}) \\ A=375000(1+\frac{36}{1825}) \\ A=\text{\$}382397.26 \end{gathered}

Therefore the interest is given as;

A-P=382397.26-375000=\text{\$}7397.26

Step 4

Find the interest in 1980 with a 20% rate

\begin{gathered} A=375000(1+(0.2\times\frac{18}{73}) \\ A=\text{\$}393493.15 \end{gathered}

The interest is given as;

A-p=393493.15-375000=\text{\$}18493.15\text{ }

Step 5

Find the difference in interest between the two rates.

\text{\$}18493.15-\text{\$}7397.26=\text{\$}11095.89

Hence, the difference in interest between the two rates = $11095.89

4 0
1 year ago
Can someone help me with this it is confusing :(
Marina CMI [18]
What are you wanting help with
7 0
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What is the percent between 4 and 3.80
crimeas [40]
0.20 so %20 because there is 20 100ths between that
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What is the rate of change in distance for the first 5 minutes of the race
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Aneli [31]
-2 / 1/4
If you are dividing you have to switch 1/4 to 4/1

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= -8
Hope this helped
6 0
3 years ago
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