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2 years ago

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Mathematics

2 answers:

Rina8888 [55]2 years ago

7 0

Answer:

Step-by-step explanation:

Given,

Cost price of the car when Arjun bought = ₹ 3,50,000

Cost price of that same car after 1 year = ₹ 3,70,000

So,

Amount of money increased on the car's price

= ₹ (3,70,000 - 3,50,000)

= ₹ 20,000

Therefore, 

Percentage of increase on the car's price

$= \frac{20000}{350000} \times 100$

[On Simplification]

$= \frac{2}{35} \times 100$

[On further Simplification]

= 5.7142......

= 5.71 (approx.)

Hence,

Percentage in increase of car's price was 5.71% (Ans)

Svet_ta [14]2 years ago

3 0

Answer:

Price of car previous year = ₹3,50,000

Price of car next year = ₹3,70,000

Increase in price = ₹3,70,000–₹3,50,000

= ₹20,000

for,

Percentage of increase in price =

$= \frac{increase \: in \: price \: }{initiall \: price \: of \: car} \times 100 \\ = \frac{20000}{350000} \times 100 \\ \\ = \frac{2}{35} \times 100 \\ \\ = \frac{200}{35} \\ \\ = > 5.7142 \: = > 5.72\%$

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3 years ago

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3 years ago

#Quality answer needed #No spam _/|\_​

#Quality answer needed #No spam _/|\_