9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Answer:
D
Step-by-step explanation:
If there are 20 students, and each team has 5 students, then there will be 4 teams of third graders that will play kickball.
20/5 = 4
Answer
1/2+2×(sqrt3)^2+x.(sqrt3/2)^2=8+1^2+1/2
1/2+2×3+x.3/4=8+1+1/2
1/2-1/2+6+x.3/4=9
x.3/4=9-6
x.3×4=3
x.3=3×4
x.3=12
x=12/3
x=4.
so, the value of x is 4.
hope it helps you.
Check the picture below.
notice, we have three pair of sides, let's add them all up to get the area
Answer:
this is the answer
Step-by-step explanation:
hope it helped!!!
